Chlorous
H+(aq)+OH−(aq)→H2O(l)
Balanced Molecular Equation:HCl(aq) + NaOH(aq) --> NaCl(aq) + H2O(l)Complete Ionic Equation:H+ (aq) + Cl- (aq) + Na+ (aq) + OH- (aq) -->Na+ (aq) + Cl- (aq) + H2O (l)Cancel out the "spectator" ions, or ions that do not change in structure or charge (on both sides of the equation; "cancel out")Net Ionic Equation:H+ (aq) + OH- (aq) --> H2O(l)User forgot to place the yield arrows (separating products from reactants)
NH4NO3(s) + H2O(l)--> NH4OH(aq) + HNO3(aq) --> NH4+(aq) + NO3-(aq) + H2O(l) The intermediate step (with ammonium hydroxide and nitric acid) doesn't really happen, it pretty much goes directly into the ion states. But that is how it would be rearranged for product formation.
H^+(aq) + C2H3O2^-(aq) + Na^+(aq) + OH^-(aq) = Na^+(aq) + C2H3O2^-(aq) + H2O(L)Reducing (by crossing out repeated [spectator] ions) gives H^+(aq) + OH^-(aq) = H2O(L)
C6H5N2 Cl (aq) + H2O(l) C6H5OH(aq) + N2 +HCl(aq)
K2Cr2O7(aq) + 3SO2(g) + H2SO4(aq) Cr2(SO4)3(aq) + K2SO4(aq) + H2O(l)
KHC8H4O4(aq) + NaOH(aq) → KNaC8H4O4(aq) + H2O(l) NaOH(aq) + KHP(aq) => Na+ + KP- + H2O(l)
Na+ + OH- + H+ + Cl- H2O + Na+ + Cl-
HClO4(aq) + NaOH(aq) → H2O(l) + NaClO4(aq) Ionic Equation: H+ + ClO4- + Na+ + OH- → H2O + Na+ + ClO4-
The reaction between selenium dioxide and aqueous potassium hydroxide forms selenites, or salts containing the SeO3^2- ion, and water. This reaction can be represented as SeO2 + 2KOH + H2O → K2SeO3 + H2O.
H+(aq)+OH−(aq)→H2O(l)
Na+(aq) + OH-(aq) + H+(aq) + Cl-(aq) -> H2O(l) + Na+(aq) + Cl-(aq)
NaOH(aq) + HCL(aq) = NaCl(aq)l + H2O(l)
Overall ionic equation: K+(aq) +OH-(aq)+ H30+(aq) + Cl-(aq)------>2H20 (l) + K+(aq) + Cl-(aq) Net ionic Equation OH-(aq)+ H30+(aq) ------>2H20 (l)
Balanced Molecular Equation:HNO2(aq) + NaOH(aq) NaNO2(aq) + H2O(l)Complete Ionic Equation: HNO2 (aq) + Na+ (aq) + OH- (aq)Na+ (aq) + NO2- (aq) + H2O (l)Net Ionic Equation: HNO2 (aq) + OH- (aq)NO2- (aq) + H2O (l)
Kb=[(Ch3)3 NH+][OH-] __________ [(Ch3)3 N]
Sulfurous Acid = H2SO3(aq) -> SO2(g) + H2O(l) Carbonic Acid = H2CO3(aq) -> CO2(g) + H2O(l) Ammonium Hydroxide = NH4OH(aq) -> NH3(g) + H2O(l) Ammounium Sulfide = (NH4)2S(aq) -> 2NH3(g) + H2S(g)