Balanced Molecular Equation:HCl(aq) + NaOH(aq) --> NaCl(aq) + H2O(l)Complete Ionic Equation:H+ (aq) + Cl- (aq) + Na+ (aq) + OH- (aq) -->Na+ (aq) + Cl- (aq) + H2O (l)Cancel out the "spectator" ions, or ions that do not change in structure or charge (on both sides of the equation; "cancel out")Net Ionic Equation:H+ (aq) + OH- (aq) --> H2O(l)User forgot to place the yield arrows (separating products from reactants)
NH4NO3(s) + H2O(l)--> NH4OH(aq) + HNO3(aq) --> NH4+(aq) + NO3-(aq) + H2O(l) The intermediate step (with ammonium hydroxide and nitric acid) doesn't really happen, it pretty much goes directly into the ion states. But that is how it would be rearranged for product formation.
H^+(aq) + C2H3O2^-(aq) + Na^+(aq) + OH^-(aq) = Na^+(aq) + C2H3O2^-(aq) + H2O(L)Reducing (by crossing out repeated [spectator] ions) gives H^+(aq) + OH^-(aq) = H2O(L)
NH3 (aq) + H2O (l) NH4+ (aq) + OH- (aq)
NH3 (aq) + H2O (l) --> NH4+ (aq) + OH- (aq)
SeO2 (s) + 2KOH(aq) > K2SeO3(aq) +H2O(l) SeO2(s)+2KOH(aq)→K2SeO3(aq)+H2O(l)
NaHCO3(aq) + CaHPO4(aq) → NaCaPO4(aq) + CO2(g) + H2O(l)
Na2S2O3(aq) + 2HCL(aq) => 2NaCl(aq) + S(s) + SO2(g) + H2O(l)
NH4+ (aq) + OH (aq) ----> NH3 (g) + H2O(l) The product, ammonia, is NH3
KHC8H4O4(aq) + NaOH(aq) → KNaC8H4O4(aq) + H2O(l) NaOH(aq) + KHP(aq) => Na+ + KP- + H2O(l)
Sulfurous Acid = H2SO3(aq) -> SO2(g) + H2O(l) Carbonic Acid = H2CO3(aq) -> CO2(g) + H2O(l) Ammonium Hydroxide = NH4OH(aq) -> NH3(g) + H2O(l) Ammounium Sulfide = (NH4)2S(aq) -> 2NH3(g) + H2S(g)
K2Cr2O7(aq) + 3SO2(g) + H2SO4(aq) Cr2(SO4)3(aq) + K2SO4(aq) + H2O(l)
HNO3 (aq) + NaOH (aq) --> H2O (l) + NaNO3 (aq)
By equilibrium only in water:Ionconcentration product = KW ,meaning:[H30+] * [OH-] = 1.0*10-14 (at 25oC)H30+(aq) + OH-(aq) > H2O(l)
Balanced Molecular Equation:HCl(aq) + NaOH(aq) --> NaCl(aq) + H2O(l)Complete Ionic Equation:H+ (aq) + Cl- (aq) + Na+ (aq) + OH- (aq) -->Na+ (aq) + Cl- (aq) + H2O (l)Cancel out the "spectator" ions, or ions that do not change in structure or charge (on both sides of the equation; "cancel out")Net Ionic Equation:H+ (aq) + OH- (aq) --> H2O(l)User forgot to place the yield arrows (separating products from reactants)
I2(l) + H2O(l) -> OI-(aq) + 2H+(aq) + I-(aq)
NH4NO3(s) + H2O(l)--> NH4OH(aq) + HNO3(aq) --> NH4+(aq) + NO3-(aq) + H2O(l) The intermediate step (with ammonium hydroxide and nitric acid) doesn't really happen, it pretty much goes directly into the ion states. But that is how it would be rearranged for product formation.