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13.16 as you need to use formula square root of ( 352.019/2.016)=13.16

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High effusion rates


Calculate the ratio of effusion rates for Ar and Kr?

The ratio of effusion rates for two gases is given by the square root of the inverse ratio of their molar masses. The molar mass of Ar is approximately 40 g/mol, and for Kr it is approximately 84 g/mol. So, the ratio of effusion rates for Ar and Kr is √(84/40) ≈ 1.3.


How do you calculate the ratio of effusion rates for nitrogen times two and neon?

To calculate the ratio of effusion rates for nitrogen (N2) and neon (Ne), use Graham's law of effusion: Ratio = (Molar mass of neon / Molar mass of nitrogen)^(1/2) For neon (Ne) with a molar mass of 20.18 g/mol and nitrogen (N2) with a molar mass of 28.02 g/mol, the ratio of their effusion rates would be approximately √(20.18 / 28.02) ≈ 0.75.


What gas would be expected to have the lowest rate of effusion?

The rate of effusion of a gas is inversely related to its molar mass, according to Graham's law of effusion. Therefore, a heavier gas, such as xenon (Xe) or carbon dioxide (CO₂), would have a lower rate of effusion compared to lighter gases like helium or hydrogen. Among common gases, xenon, with a high molar mass of approximately 131.3 g/mol, would be expected to have one of the lowest rates of effusion.


Which stateWhich statement about the effusion rates of nitrogen and oxygen is truement about the effusion rates of nitrogen and oxygen is true?

The rate of effusion is inversely related to the square root of the molar mass. Or stated another way, the larger or heavier the gas, the slower the effusion rate. Nitrogen gas (N2) has a molar mass of 28 g/mole and oxygen gas (O2) has a molar mass of 32 g/mole. Nitrogen will diffuse faster. rate N2/rate O2 = sqrt 32/sqrt 28 = 5.66/5.29 = 1.07. So, N2 effuses 1.07x faster than O2, or 7% faster. For more information on this, look up Graham's Law of Effusion.


What gas effuses four times as fast as oxygen?

Helium is a gas that effuses four times faster than oxygen. This is because helium has a lower molar mass compared to oxygen, leading to faster effusion rates as per Graham's law of effusion.


How can you compare the rates of effusion of two gases in a mixture?

The rate of effusion of gases is inversely proportional to the square root of their molar masses. By comparing the molar masses of the two gases, you can determine which gas effuses faster. The gas with the lower molar mass will effuse more quickly.


Where is the rain the heaviest in a hurricane?

The rain is heaviest in a hurricane near the center of the storm, which is called the eye wall. The eye wall is where the strongest winds and most intense rainfall occur, with rainfall rates reaching several inches per hour.


What is the ratio of effusion rates between helium and radon gas?

The ratio of effusion rates between helium and radon gas is approximately √(Molar mass of gas 2 / Molar mass of gas 1), which in this case would be √(222 / 4) = √55.5 ≈ 7.46. This means that radon gas effuses approximately 7.46 times slower than helium gas under the same conditions.


How quickly does snow fall in the heaviest snow storm?

In the heaviest snowstorms, snow can fall at rates exceeding 2 to 4 inches per hour, with some extreme events producing snowfall rates of up to 6 inches per hour or more. These intense rates often occur during blizzards, where strong winds and low temperatures contribute to rapid accumulation. The exact rate can vary based on factors such as temperature, humidity, and the specific characteristics of the storm.


How much faster does nitrogen monoxide effuse in comparison to dinitrogen tetroxide(N2O4)?

To compare the effusion rates of nitrogen monoxide (NO) and dinitrogen tetroxide (N2O4), we can use Graham's law of effusion, which states that the rate of effusion is inversely proportional to the square root of the molar masses of the gases. The molar mass of NO is approximately 30 g/mol, while that of N2O4 is about 92 g/mol. Therefore, nitrogen monoxide effuses faster than dinitrogen tetroxide, specifically, it effuses approximately 1.73 times faster (√(92/30) ≈ 1.73).


How much faster do ammonia molecules effuse than carbon monoxide molecules?

Effusion goes as the inverse square root of the molecular weight (Graham's Law). The rest is simple algebra.