Copper is multivalent but its most common valence is 2- so the equation should look like this:
Cu (s) + H2O (l) ---> Cu(OH)2 (s) + H2 (g)
Copper metal reacts with liquid water to form Copper Hydroxide and Hydrogen gas
The reaction between Copper II hydroxide and heat is a decomposition reaction. When heated, Copper II hydroxide breaks down into copper oxide and water vapor.
Sodium hydroxide is commonly used to make copper sulfate from copper oxide, which is insoluble in water. The reaction between copper oxide and sodium hydroxide forms copper sulfate and water.
The reaction between sodium hypochlorite and copper results in the formation of copper(II) oxide and sodium chloride. This is an oxidation-reduction reaction where the sodium hypochlorite oxidizes the copper metal to form copper oxide and is itself reduced to sodium chloride.
Heating copper sulfate pentahydrate leads to a dehydration reaction, where water molecules are removed from the compound. This results in the formation of anhydrous copper sulfate.
Lead is less reactive than copper, so the sulphate ion would stay bound to the copper, so the answer is the same compounds as you started with.
no reaction take place between copper and water. so there is no blance equation.
When glucose reacts with copper oxide in the presence of lime water, a redox reaction occurs where glucose is oxidized to produce carbon dioxide and water. The copper oxide is reduced to copper metal. The lime water is not directly involved in the reaction but can be used to test for the presence of carbon dioxide produced in the reaction.
The reaction between copper oxide and sulfuric acid will produce copper sulfate and water. Copper sulfate is a blue crystalline solid, while water is formed as a byproduct of the reaction.
When copper oxide reacts with hydrogen, it forms copper metal and water. The balanced chemical equation for this reaction is: CuO + H2 → Cu + H2O. This is a reduction-oxidation (redox) reaction where copper oxide is reduced and hydrogen is oxidized.
The reaction between copper oxide and sulfuric acid is a chemical reaction that results in the formation of copper sulfate and water. This is an example of an acid-base reaction, where the acid (sulfuric acid) reacts with the base (copper oxide) to form a salt (copper sulfate) and water.
The reaction between Copper II hydroxide and heat is a decomposition reaction. When heated, Copper II hydroxide breaks down into copper oxide and water vapor.
The products of the reaction between copper sulfate and hydrogen peroxide are copper oxide, water, and oxygen gas. Specifically, the copper sulfate is reduced to copper oxide, while hydrogen peroxide is decomposed into water and oxygen gas.
A penny turns green in water due to a chemical reaction between the copper in the penny and the oxygen in the water. This reaction forms a layer of copper oxide on the surface of the penny, giving it a greenish tint.
The reaction between copper, water, and oxygen to form copper hydroxide is a chemical reaction that involves oxidation. Copper reacts with oxygen in the air to form copper oxide, which then reacts with water to give copper hydroxide. This reaction can be classified as both oxidation and hydrolysis.
This type of reaction is called Combination or Synthesis reaction.Hot and concentrated Sulphuric acid reacts with copper to produce Copper(II) sulphate, water and Sulphur dioxide.Cu + 2 H2SO4----> CuSO4 + 2H2O + SO2
Copper oxide reacts with sulfuric acid to form copper sulfate and water. The word equation is: Copper oxide + sulfuric acid → copper sulfate + water.
The word equation for the reaction between iron sulfate and copper is: iron sulfate + copper → copper sulfate + iron.