l = 1
l=0
ml=0
l=1
Phosphorus has 15 electrons. The electron distribution in a phosphorus atom is 2 electrons in the first energy level, 8 electrons in the second energy level, and 5 electrons in the third energy level.
Phosphorus has 5 electrons in its outermost principal energy level.
The second quantum number refers to the azimuthal quantum number, also known as the angular momentum quantum number. For an electron in the 1s orbital of phosphorus (1s2), the azimuthal quantum number is 0, which corresponds to an s orbital. Therefore, for a 1s2 electron in phosphorus, the second quantum number would be 0.
l=0
The second quantum number, also known as the azimuthal quantum number (l), describes the shape of an electron's orbital. For the 2s orbital, l equals 0, indicating a spherical shape. Therefore, the second quantum number of the 2s² electron in phosphorus is 0.
l=0
l=0
ml=0
l=1
The first quantum number, also known as the principal quantum number (n), indicates the energy level of an electron in an atom. For a 2s electron in phosphorus, which has an electron configuration of 1s² 2s² 2p⁶ 3s² 3p³, the principal quantum number is 2. This indicates that the electron is located in the second energy level.
The second quantum number (angular momentum quantum number) for a 3p electron is 1. This indicates the electron is in the p subshell, which has angular momentum quantum number values of -1, 0, 1.
In the electron configuration of aluminum, the 3p1 electron corresponds to the 3rd energy level (n=3) and is in the p subshell. The second quantum number, also known as the azimuthal quantum number (l), for a p subshell is 1. Therefore, the second quantum number of the 3p1 electron in aluminum is l = 1.
The principal quantum number n = 3 and the azimuthal or orbital angular momentum quantum number would be l =1 .l = 1
The type of orbital the electron is in.