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This problem uses the ideal gas law: PV = nRT

P is the pressure in ATM, V is the volume in liters, n is the number of moles, R is a constant (0.08206 (L ATM)/(mole K)), and T is the temperature in Kelvin. To go from Kelvin to Celsius, subtract 273.15.

All you need to go is find the number of moles of oxygen and plug in the other numbers.

To find the moles of oxygen: the molar mass of O2 is 2*16 g/mol = 32 g/mol.

2 g / 32 g/mol = .0625 moles

So you have:

1.21 ATM * 2 L = .0625 moles * 0.08206 (L ATM)/(mol K) * T K

Solve for T in Kelvin:

(1.21*2) / (.0625*.08206) = 471.8499 K

To convert that to Celsius:

471.8498 - 273.15 = = 198.6998 °C

I'm not sure how many significant figures you have given the way the question is worded, but the answer to 3 significant digits is: 199 °C

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