This problem uses the ideal gas law: PV = nRT
P is the pressure in ATM, V is the volume in liters, n is the number of moles, R is a constant (0.08206 (L ATM)/(mole K)), and T is the temperature in Kelvin. To go from Kelvin to Celsius, subtract 273.15.
All you need to go is find the number of moles of oxygen and plug in the other numbers.
To find the moles of oxygen: the molar mass of O2 is 2*16 g/mol = 32 g/mol.
2 g / 32 g/mol = .0625 moles
So you have:
1.21 ATM * 2 L = .0625 moles * 0.08206 (L ATM)/(mol K) * T K
Solve for T in Kelvin:
(1.21*2) / (.0625*.08206) = 471.8499 K
To convert that to Celsius:
471.8498 - 273.15 = = 198.6998 °C
I'm not sure how many significant figures you have given the way the question is worded, but the answer to 3 significant digits is: 199 °C
Oxygen boils at a temperature of -182.96 degrees Celsius (-297.33 degrees Fahrenheit) at standard atmospheric pressure.
Under normal atmospheric pressure oxygen is a liquid at temperatures ranging from -218.79 degrees Celsius to -182.96 degrees Celsius. This works out to -361.82 degrees Fahrenheit to -297.33 degrees Fahrenheit.
The pressure inside the cylinder of oxygen will increase as the temperature rises. This is because an increase in temperature causes the oxygen molecules to move faster and collide with the walls of the cylinder more frequently, resulting in a higher pressure.
Standard temperature and pressure (STP) for oxygen is defined as a temperature of 0 degrees Celsius (273.15 Kelvin) and a pressure of 1 atmosphere (101.325 kilopascals). At STP, one mole of oxygen gas occupies a volume of 22.4 liters.
At 1000 degrees Celsius, oxygen exists in a gaseous state. This high temperature well exceeds oxygen's boiling point of -183 degrees Celsius, causing it to be present as a gas.
Oxygen boils at a temperature of -182.96 degrees Celsius (-297.33 degrees Fahrenheit) at standard atmospheric pressure.
Oxygen liquefies at a temperature of -183 degrees Celsius under normal atmospheric pressure.
Under normal atmospheric pressure oxygen is a liquid at temperatures ranging from -218.79 degrees Celsius to -182.96 degrees Celsius. This works out to -361.82 degrees Fahrenheit to -297.33 degrees Fahrenheit.
At 50 degrees Celsius, oxygen is in a gaseous state. It is a diatomic molecule in its standard state at room temperature and pressure.
The pressure inside the cylinder of oxygen will increase as the temperature rises. This is because an increase in temperature causes the oxygen molecules to move faster and collide with the walls of the cylinder more frequently, resulting in a higher pressure.
A gram of oxygen is equivalent to approximately 0.56 liters at standard temperature and pressure (STP), which is 0 degrees Celsius and 1 atmosphere of pressure.
At 1000 degrees Celsius, oxygen exists in a gaseous state. Oxygen gas (O2) is a colorless and odorless gas at this temperature.
Standard temperature and pressure (STP) for oxygen is defined as a temperature of 0 degrees Celsius (273.15 Kelvin) and a pressure of 1 atmosphere (101.325 kilopascals). At STP, one mole of oxygen gas occupies a volume of 22.4 liters.
Oxygen is a gas at 20 degrees Celsius. It has a boiling point of -183 degrees Celsius and a melting point of -218 degrees Celsius, so at room temperature, oxygen exists as a gas.
negative 219 degrees Celsius
The freezing or melting point of oxygen is -218.8 degrees Celsius or 54.36 Kelvin.
At 1000 degrees Celsius, oxygen exists in a gaseous state. This high temperature well exceeds oxygen's boiling point of -183 degrees Celsius, causing it to be present as a gas.