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Q: What is the valency of M in M3O4?
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What is the formula of the second compound if two oxides of a metal contain 27.6 percent and 30 percent of oxygen respectively and if the formula of the first compound is M3O4?

Formula of first oxide = M3O4 let mass of the metal be == x percentage of metal in M3O4 = (3x/ 3x+64) *100 but % age = (100-27.6) = 72.4 % so, (3x/ 3x+64)*100 = 72.4 or x = 56. in 2nd oxide, oxygen = 30%....so metal = 70% so, ratio :-- M : O 70/56 : 30/16 1.25 : 1.875 2 : 3 so, 2nd oxide = M2O3


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