Copper want to give up it's valence electrons, therefore it is a positive cation when ionized. Answers appear to be 1+ and 2+. Typically metals have positive ions. The charge of copper can be determined by evaluating the anion charge(s) and then solving the cation side.
Copper can have a +1 charge, known as cuprous ion, and a +2 charge, known as cupric ion. These charges depend on the oxidation state of copper in a compound.
The valency of the chromate ion is 2-. This means that the chromate ion has a charge of -2.
Actually, the answer Cu(NO3)2 is incorrect for cuprous nitrate. Cu(NO3)2 is in fact cupric nitrate. Cuprous nitrate is represented as CuNO3 alone.
The valency of the silicate ion is -4, meaning it has a charge of -4. This is because the silicate ion is made up of one silicon atom (which has a valency of +4) and four oxygen atoms (each with a valency of -2).
If you add Copper in Cupric Chloride at the time of reaction, it will turn into Cuprous Chloride. But it will again turn into Cupric Chloride if you continue the reaction. This is actually a Exo-Thermic reaction.
I think cuprous oxide has a charge of 1+, while cupric oxide has a charge of 2+. Cupric oxide is also more stable than cuprous oxide.
Cupric refers to copper in the +2 oxidation state, while cuprous refers to copper in the +1 oxidation state. Cupric compounds are blue/green in color, while cuprous compounds are white or pale yellow.
Copper can have a +1 charge, known as cuprous ion, and a +2 charge, known as cupric ion. These charges depend on the oxidation state of copper in a compound.
a cuprous ion has 28 electrons.
"Cuprous" is an archaic term for what today is called copper (I), Cu+1.
Its Valency = 2the formula being CuOThe copper donates two electrons to the oxygen and forms one ionic bond.Added:There are two copper oxides, differing in color:if it is black powder, then it is copper(II) oxide CuO (cupric, more common, as in the mineral 'tenoriet')if it is red powder, then it is copper(I) oxide Cu2O (cuprous oxide, as in mineral the 'cupriet' and it occurs in 'Benedict's test' on reducing sugars)
The charge on cuprous ion is +2. It is written as Cu2+.
Fehling's solution is prepared just before use by mixing equal volumes of two previously prepared solutions, one containing about 70 grams cupric sulfate pentahydrate per liter of solution and the other containing about 350 grams Rochelle salt (potassium sodium tartrate tetrahydrate) and 100 grams sodium hydroxide per liter of solution. The cupric ion (complexed with tartrate ion) is reduced to cuprous ion by the aldehyde (which is oxidized) and precipitates as cuprous oxide (Cu2O). So the tartrate part of Rochelle salt is the key reactant. In the case of sodium citrate: the cupric ion (complexed with citrate ions) is reduced to cuprous ion by the aldehyde group (which is oxidized), and precipitates as cuprous oxide, Cu2O. Thus the citrate is key to the reaction.
These compounds can alternatively be named copper(I) and copper(II) oxides; these so-called "Stock system" names seem to be preferred by most current textbooks of chemistry over the designations cuprous and cupric.
Yes, it will. Maltose has a free aldehyde group in its linear form, then this aldehyde reduces Cu2+ forming the cuprous oxide (CuO) which is a reddish precipitate. This is the Fehling reaction.
The valency of the chromate ion is 2-. This means that the chromate ion has a charge of -2.
Actually, the answer Cu(NO3)2 is incorrect for cuprous nitrate. Cu(NO3)2 is in fact cupric nitrate. Cuprous nitrate is represented as CuNO3 alone.