At STP, Standard Temperature and Pressure, one mole of gas takes up 24dm3 of volume. One mole of nitrogen weighs 14g, so in 888g there are 63.4 moles of nitrogen. This takes up a volume of 63.4 x 24 = 1522.3dm3.
The molar mass of CO2 is 44.01 g/mol. Using the ideal gas law, we can calculate the number of moles of CO2 in 15.0 kg (15000 g). At STP conditions, 1 mole of gas occupies 22.4 L, so once you find the number of moles, you can convert that to liters.
Density of CO2 at STP = 44.01 g/mol divided by the 22.4 liters. 1.96 grams/Liter
There are several different possible reactions of Fe2O3 with CO, depending on temperature and ratio of reactants. The simplest is probably Fe2O3 + CO ==>2FeO + CO21.00 Kg x 1000 g/Kg x 1 mole Fe2O3/160 g = 6.25 moles Fe2O3 moles CO2 produced = 6.25 moles CO2 Volume CO2 at STP = 6.25 moles x 22.4 L/mole = 140 Liters
Assuming complete reaction, the molar mass of CaCO3 is approximately 100.09 g/mol. One mole of CaCO3 produces one mole of CO2. Therefore, 10 grams of CaCO3 will produce approximately 2.24 liters of CO2 at STP (22.4 L/mol).
To determine the limiting reagent, we need to compare the amount of CO2 that could be produced from each reactant. First, convert the volumes to moles using the ideal gas law. Then, use the coefficients from the balanced chemical equation to find the amount of CO2 that each reactant could produce. The limiting reagent is the one that produces the least amount of CO2. The volume of CO2 formed can be calculated using the stoichiometry of the limiting reagent.
At standard temperature and pressure (STP), which is defined as 0 degrees Celsius and 1 atmosphere pressure, the volume of 10 grams of CO2 can be calculated using the ideal gas law. The molar mass of CO2 is 44.01 g/mol. Using the ideal gas law equation, you can determine the volume to be approximately 4.48 liters.
The molar mass of CaCO3 is 100.09 g/mol, and the molar mass of CO2 is 44.01 g/mol. By using stoichiometry, you can calculate that 15.2 grams of CaCO3 would produce 6.51 grams of CO2. Using the ideal gas law, you can then convert the mass of CO2 to volume using its molar volume at STP (22.4 L/mol). The volume of CO2 produced would be around 3.32 liters.
The molar mass of CO2 is 44.01 g/mol. Using the ideal gas law, we can calculate the number of moles of CO2 in 15.0 kg (15000 g). At STP conditions, 1 mole of gas occupies 22.4 L, so once you find the number of moles, you can convert that to liters.
Under these conditions, the volume will be directly proportional to the number of moles. And the number of moles varies with the number of grams. 110 g/30 g = 3.67, so there are 3.67 x more moles in 110 g as there are in 30 g. And the volume will be 3.67 x greater or 3.67 x 410 ml = 1503 ml = 1.5 liters (to 2 significant figures)
The volume of ammonia is 19,5 L.
Density of CO2 at STP = 44.01 g/mol divided by the 22.4 liters. 1.96 grams/Liter
At STP conditions (standard temperature and pressure), the volume occupied by 1 mole of ideal gas is 22.4 liters. Since the molar mass of SO2 is approximately 64 g/mol, 11 g of SO2 is about 0.172 moles. Therefore, the volume of 11 g of SO2 at STP would be approximately 3.85 liters.
0.00922 g of H2 gas will occupy approximately 0.100 L at STP
There are several different possible reactions of Fe2O3 with CO, depending on temperature and ratio of reactants. The simplest is probably Fe2O3 + CO ==>2FeO + CO21.00 Kg x 1000 g/Kg x 1 mole Fe2O3/160 g = 6.25 moles Fe2O3 moles CO2 produced = 6.25 moles CO2 Volume CO2 at STP = 6.25 moles x 22.4 L/mole = 140 Liters
Assuming complete reaction, the molar mass of CaCO3 is approximately 100.09 g/mol. One mole of CaCO3 produces one mole of CO2. Therefore, 10 grams of CaCO3 will produce approximately 2.24 liters of CO2 at STP (22.4 L/mol).
The ideal gas law states that at STP (Standard Temperature and Pressure), one mole of gas occupies 22.4 L of volume. Boron trifluoride (BF3) has a molar mass of 67.8 g/mol. Therefore, 0.155 g of boron trifluoride is 0.155/67.8 = 0.00228 moles. At STP, this amount of boron trifluoride would occupy 0.00228 * 22.4 = 0.051072 L of volume.
The density of CO2 gas at standard temperature and pressure (STP) is approximately 1.977 g/L. This value is derived from the molar mass of carbon dioxide (44.01 g/mol) divided by the molar volume at STP (22.4 L/mol). The calculation is as follows: 44.01 g/mol / 22.4 L/mol = 1.977 g/L. This density value is useful in various applications, such as in gas laws and stoichiometry calculations.