15kg = 15000g. 15000g/44gmol-1 = 341mol. 341 x 22.4Lmol-1 = 7600L at STP.
The volume is 7 587,25 litres.
22.4 liters at STP
We know that one mole of any gas at STP occupies 22.4 liters of volume. We also know that one mole of carbon dioxide is 44.01 grams of CO2. If there are 44.01 grams of this gas in 22.4 liters at STP, then there will be about 0.98 grams of CO2 in half a liter (500 ml) of the gas at STP.
1 mole occupies 22.4 liters. 0.5 moles occupies 11.2 liters at STP.
Not sure what you mean by "first letter is a c", but the volume of one mole of an ideal gas at STP is 22.4 Liters.
61ml
22.4 liters at STP
We know that one mole of any gas at STP occupies 22.4 liters of volume. We also know that one mole of carbon dioxide is 44.01 grams of CO2. If there are 44.01 grams of this gas in 22.4 liters at STP, then there will be about 0.98 grams of CO2 in half a liter (500 ml) of the gas at STP.
The volume of CO2 is 4,94 L.
5126 cm3
The volume is 64,8 L.
1 mole occupies 22.4 liters. 0.5 moles occupies 11.2 liters at STP.
Not sure what you mean by "first letter is a c", but the volume of one mole of an ideal gas at STP is 22.4 Liters.
61ml
Because you're in STP conditions, you can use molar volume in a proportion. Molar volume is the volume one mole of an ideal gas will take up at STP: 22.4 liters/mole. To set up a proportion, think: if one mole of a gas occupies 22.4 liters, then 4.0 moles of a gas will occupy x liters.1 mole/22.4 L = 4.0 mole/X Lx = 44.8 liters
The volume is 19,48 L.
1 mole of gas at STP occupies 22.4 liters.
Acetylene is C2H2, with a molar mass of 26g/mol. 49.6g of it = 1.9 moles. At STP, 1 mole of any gas occupies a volume of 22.4 liters, so 1.9 moles at STP would have a volume of 42.56 liters.