The (already) balanced reaction equation itself (assuming that there should be an arrow in the equation between "3" and "2") shows that 3 moles of water are produced from every 6 moles of HCl that is reacted. The gram molecular mass of HCl is 36.46 and that of water is 18.02. Therefore, the ratio of the mass of water produced to the mass of hydrogen chloride reacted is [3(18.02)]/[6(36.45)], or 0.2472, to the justified number of significant digits. (The integers "2" and "3" in the ratio are exact.)
The mass of water produced is therefore (0.2472)(12.0) or 2.97 grams, to the justified number of significant digits.
66g
42 , and 28.
888
Balanced equation first. N2 + 3H2 >> 2NH3 (hydrogen is limiting and drives the reaction ) 3.41 grams H2 (1mol/2.016g )(2mol NH3/3mol H2 )(17.034g NH3/1mol NH3 ) = 19.2 grams of ammonia produced ( this is called the Born-Haber process )
i bet its 2.0g
If 15 liters of propane are completely consumed 90,25 grams of carbon dioxide are produced.
18 grams
66g
42 , and 28.
I assume KOH is limiting. Balanced equation. KOH + HCl -> KCl + H2O 0.400 moles KOH (1 mole H2O/1 mole KOH)(18.016 grams/1 mole H2O) = 7.21 grams water produced =====================
7.8 grams
Balanced equation first. 2Na + 2HCl >> 2NaCl + H2 25 grams Na (1mol Na/22.99g )(1mol H2/2mol Na ) = 0.54 moles of H2 produced.
C + O2 ------> CO2 is the reaction equation. 1 mole of C + 1 mole of O2 makes 1 mole of CO2.
888
The total number of moles of NO produced when 1,0 mole of O2 is completely consumed is 2.
96.75 grams of NaCl
322 grams.