The (already) balanced reaction equation itself (assuming that there should be an arrow in the equation between "3" and "2") shows that 3 moles of water are produced from every 6 moles of HCl that is reacted. The gram molecular mass of HCl is 36.46 and that of water is 18.02. Therefore, the ratio of the mass of water produced to the mass of hydrogen chloride reacted is [3(18.02)]/[6(36.45)], or 0.2472, to the justified number of significant digits. (The integers "2" and "3" in the ratio are exact.)
The mass of water produced is therefore (0.2472)(12.0) or 2.97 grams, to the justified number of significant digits.
The balanced chemical equation for the combustion of glucose (C6H12O6) is: C6H12O6 + 6O2 -> 6CO2 + 6H2O. From the equation, we can see that 1 mol of C6H12O6 produces 6 mol of CO2. First, calculate the number of moles of C6H12O6 in 45 g. Then use the mole ratio to find the moles of CO2 produced, and finally convert that to grams.
The balanced chemical equation for the reaction of hydrogen and oxygen to form water is 2H2 + O2 -> 2H2O. Based on the equation, for every 2 grams of hydrogen, 64 grams of oxygen are needed to form 36 grams of water. Thus, if 8 grams of hydrogen react completely with 64 grams of oxygen, the total mass of water formed would be 36 grams.
The chemical equation for the combustion of glucose is C6H12O6 + 6O2 -> 6CO2 + 6H2O. From this, we can see that 1 mole of glucose produces 6 moles of CO2. Therefore, 45 grams of glucose (which is approximately 0.25 moles) would produce 6 times that amount of CO2, which is about 90 grams.
To find the mass of CO2 produced, first calculate the moles of C2H4 using its molar mass. Then, use the balanced equation to determine the moles of CO2 produced per mole of C2H4 reacted. Finally, convert moles of CO2 to grams using the molar mass of CO2.
To calculate the amount of AlO produced, you first need to determine the limiting reactant by converting the grams of Al and FeO to moles, then comparing their molar ratios. Once you find the limiting reactant, use stoichiometry to calculate the moles of AlO produced. Finally, convert the moles of AlO to grams. The same steps can be used to find the amount of Fe produced.
If 15 liters of propane are completely consumed 90,25 grams of carbon dioxide are produced.
It depends on the chemical reaction that is occurring. Can you provide the balanced equation for the reaction so we can calculate the amount of NaCl produced?
To find the mass of H₂O produced, first balance the equation: 2 HCl + Na₂CO₃ → 2 NaCl + H₂O + CO₂. Then calculate the number of moles of HCl in 12.0 grams, use stoichiometry to find the moles of H₂O produced, and finally convert moles of H₂O to grams using the molar mass of water (18.015 g/mol).
To calculate the mass of water produced when 32 grams of copper is consumed, we need to use the stoichiometry of the reaction. Given the balanced chemical equation for the reaction of copper with water, we can determine the moles of copper reacting and then use the mole ratio to find the moles of water produced. Finally, using the molar mass of water, we can calculate the mass of water produced.
The balanced chemical equation for the combustion of glucose (C6H12O6) is: C6H12O6 + 6O2 -> 6CO2 + 6H2O. From the equation, we can see that 1 mol of C6H12O6 produces 6 mol of CO2. First, calculate the number of moles of C6H12O6 in 45 g. Then use the mole ratio to find the moles of CO2 produced, and finally convert that to grams.
The balanced chemical equation for the reaction of hydrogen and oxygen to form water is 2H2 + O2 -> 2H2O. Based on the equation, for every 2 grams of hydrogen, 64 grams of oxygen are needed to form 36 grams of water. Thus, if 8 grams of hydrogen react completely with 64 grams of oxygen, the total mass of water formed would be 36 grams.
This question seems to be about the reactant side of a chemical equation. To calculate the mass of oxygen produced, you need to know the stoichiometry of the reaction. Without that information, it is not possible to determine why 160 grams of oxygen would be produced.
When 1.0 mole of O2 is completely consumed in the reaction to form NO, 1.0 mole of NO is produced since the balanced equation for the reaction is 2 O2 + 2 N2 -> 2 NO. This means that the mole ratio between O2 and NO is 1:1.
The amount of product formed in a reaction is determined by the stoichiometry of the reaction. Without the specific reaction given, we can't determine the grams of product produced from 22.4g of a reactant. The balanced chemical equation is needed to calculate the amount of product formed.
The chemical equation for the combustion of glucose is C6H12O6 + 6O2 -> 6CO2 + 6H2O. From this, we can see that 1 mole of glucose produces 6 moles of CO2. Therefore, 45 grams of glucose (which is approximately 0.25 moles) would produce 6 times that amount of CO2, which is about 90 grams.
To calculate the grams of CO2 produced by burning 22 grams of C3H8, first determine the moles of C3H8 using its molar mass, then use the balanced chemical equation for the combustion of C3H8 to find the moles of CO2 produced, and finally convert moles of CO2 to grams using the molar mass of CO2.
To calculate the amount of C2H2 produced from H2O, we need to consider the stoichiometry of the reaction. The balanced equation for the reaction is 2H2O -> 2H2 + O2 -> 2C2H2. From 80 grams of H2O, we can calculate the amount of C2H2 produced using stoichiometry.