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What is the percent composition by mass of phosphorous in ammonium phosphate?
Ammonium phosphate ((NH4)3PO4) contains one phosphorus atom in the formula. To calculate the percent composition by mass of phosphorus, you need to find the molar mass of phosphorus and the molar mass of the entire compound. Then, divide the molar mass of phosphorus by the molar mass of the compound and multiply by 100 to get the percentage.
What is the mass percent of hydrogen in ammonium phosphate?
The chemical formula for ammonium phosphate is (NH4)3PO4. To calculate the mass percent of hydrogen, you first need to calculate the molar mass of the entire compound and then determine the contribution of hydrogen to the total mass. The molar mass of (NH4)3PO4 is 149.09 g/mol, and the total mass of hydrogen in the compound is 3*(1.01 g/mol) = 3.03 g. Therefore, the mass percent of hydrogen in ammonium phosphate is (3.03 g / 149.09 g) * 100% = 2.03%.
What is the mass percent of hydrogen in ammonium phosphate NH4 3PO4?
To find the mass percent of hydrogen in ammonium phosphate NH4 3PO4, first calculate the total molar mass of the compound. Then, determine the molar mass contributed by hydrogen. Finally, divide the molar mass of hydrogen by the total molar mass of the compound and multiply by 100 to get the mass percent.
What is the percentage of phosphorus in ammonium phosphate?
1.) Find Ammonium phosphate's formula: (NH4)3PO4. 2.) Find the molar mass. (the sum of all the atomic masses) N's mm = 14 (but there's 3 in the molecule, so *3) = 42 H's mm= 1 (*12) = 12 P's mm: 31 O's mm: 16 (*4) = 64 42 + 12 + 31 +64 = 149 grams. 3.) Use Stoichiometry (or data analysis) to find percentage of phosphorus. Percent = part/whole. We already found out that P's mm is 31 grams. (that's the part.) And we've already found out that the whole thing is 149 grams. (that's the whole.) So... 31/149 = .20805 3.) multiply by 100 to get the percent: .20805 * 100 = 20.805 or approx. 21%
Is phosphate flamable?
Phosphate ions are not flammable or even combustible, because the phosphorus atoms in them already have the highest available formal charge of +5 for phosphorus. An organic phosphate might be flammable if it contains a sufficiently large proportion of carbon and hydrogen in its total mass.
What is the percent composition by mass of phosphorous in ammonium phosphate?
Ammonium phosphate ((NH4)3PO4) contains one phosphorus atom in the formula. To calculate the percent composition by mass of phosphorus, you need to find the molar mass of phosphorus and the molar mass of the entire compound. Then, divide the molar mass of phosphorus by the molar mass of the compound and multiply by 100 to get the percentage.
What is the mass percentage of ammonium hydrogen phosphate?
The chemical formula is (NH4)HPO4 (if you think to this phosphate). The molar mass is 132,07. The percentages of the elements are: - hydrogen: 6,86997 % - nitrogen: 21,21196 % - oxygen: 48,45843 % - phosphorous: 23,45964 %
What is the mass percent of hydrogen in ammonium phosphate?
The chemical formula for ammonium phosphate is (NH4)3PO4. To calculate the mass percent of hydrogen, you first need to calculate the molar mass of the entire compound and then determine the contribution of hydrogen to the total mass. The molar mass of (NH4)3PO4 is 149.09 g/mol, and the total mass of hydrogen in the compound is 3*(1.01 g/mol) = 3.03 g. Therefore, the mass percent of hydrogen in ammonium phosphate is (3.03 g / 149.09 g) * 100% = 2.03%.
What is the atomic mass of phosphate?
if you mean phosphorus then the atomic mass is 30.973762. i don't think phosphate is an element.
How many ammonium ions are present in 10.7g of ammonium phosphate?
The formula for the most common form of ammonium phosphate is (NH4)3PO4.3 H2O, and its gram formula mass is 203.13. The formula shows that there are 3 ammonium ions in each formula unit. 10.7g/203.13 is 5.27 X 10-2 formula units. Therefore, the number of ammonium ions present in 10.7g of this ammonium phosphate is 3 X 5.27 X 10-2 X Avogadro's Number or 9.52 X 1019 ammonium ions, to the justified number of significant digits.
How many grams of phosphorus are in 500 grams of calcium phosphate?
The mass of phosphorus of any sample of calcium phosphate is the mass of the same multiplied by the percentage that phosphorus makes up of that sample. (mass of sample) x (mass of phosphorus/total mass) Therefore we must look at the chemical formula of the substance in question: Ca3(PO4)2. From this we can see that there are 2 phosphorus atoms attributing mass to the total molecule. The formula becomes: 500 g x 2x30.97 g/mol/310.17 g/mol = 99.8 g molar mass of phosphorus: 30.97 g/mol molar mass of calcium phosphate: 310.17 g/mol total mass: 500 g
What is the molar mass ammonium phosphate(NH4)3PO4?
14x3+12+31+16x4=149 The molar mass of NH43PO4 is 149.
What is the mass percent of hydrogen in ammonium phosphate NH4 3PO4?
To find the mass percent of hydrogen in ammonium phosphate NH4 3PO4, first calculate the total molar mass of the compound. Then, determine the molar mass contributed by hydrogen. Finally, divide the molar mass of hydrogen by the total molar mass of the compound and multiply by 100 to get the mass percent.
Is phosphate an element?
Yes, Atomic mass of 75 in the periodic table!
What is the percentage of phosphorus in ammonium phosphate?
1.) Find Ammonium phosphate's formula: (NH4)3PO4. 2.) Find the molar mass. (the sum of all the atomic masses) N's mm = 14 (but there's 3 in the molecule, so *3) = 42 H's mm= 1 (*12) = 12 P's mm: 31 O's mm: 16 (*4) = 64 42 + 12 + 31 +64 = 149 grams. 3.) Use Stoichiometry (or data analysis) to find percentage of phosphorus. Percent = part/whole. We already found out that P's mm is 31 grams. (that's the part.) And we've already found out that the whole thing is 149 grams. (that's the whole.) So... 31/149 = .20805 3.) multiply by 100 to get the percent: .20805 * 100 = 20.805 or approx. 21%
What is the percentage by mass of nitrogen in ammonium phosphate NH43PO4. Remember a subscript outside parentheses is multiplied by every subscript inside the parentheses?
28.2%
How many atoms of phosphorus are in 4.8 moles of copper II phosphate?
Because copper (II) cations have a charge of +2 and phosphate anions have a charge of -3, the formula of anhydrous* copper (II) phosphate is Cu3(PO4)2. This shows that each formula unit contains 2 atoms of phosphorus. Therefore, the atoms of phosphorus in 4.8 formula units is 4.8 x Avogadro's Number, or about 2.9 X 1024 atoms, to the justified number of significant digits. ____________________________________ The answer to the problem will be the same if hydrated copper (II) phosphate is assumed, because the water of hydration contains no phosphorus and the quantity is specified in moles or formula units, but the formula would be different.
