The percentage of H in ammonium phosphate is the mass of H divided by the mass of the entire compound.
42.93
149
45.3g/Mmass phosphate x 4mol PO4/1mol x molar mass of ammonium phosphate
14.58%
The formula of ammonium sulphate is (NH4)2SO4, showing that each formula mass contains one sulphur atom. The formula mass of ammonium sulphate is 132.13, and the gram atomic mass of sulphur is 32.06. Therefore, the percent by mass of sulphur in ammonium sulphate is 100(32.06/132.13) or 24.26, to the justified number of significant digits.
42.93
149
The chemical formula is (NH4)HPO4 (if you think to this phosphate). The molar mass is 132,07. The percentages of the elements are: - hydrogen: 6,86997 % - nitrogen: 21,21196 % - oxygen: 48,45843 % - phosphorous: 23,45964 %
45.3g/Mmass phosphate x 4mol PO4/1mol x molar mass of ammonium phosphate
The percentage of nitrogen is 29,16 %.
14.58%
(NH4)3PO4 1 molecule weight = 149.09 a.m.u.3*4 = 12 H atoms weight 12*1.008 = 12.096 a.m.u.mass percentage of H in (NH4)3PO4is [12.096 / 149.09] * 100% = 8.113 %
The formula of ammonium sulphate is (NH4)2SO4, showing that each formula mass contains one sulphur atom. The formula mass of ammonium sulphate is 132.13, and the gram atomic mass of sulphur is 32.06. Therefore, the percent by mass of sulphur in ammonium sulphate is 100(32.06/132.13) or 24.26, to the justified number of significant digits.
The formula for the most common form of ammonium phosphate is (NH4)3PO4.3 H2O, and its gram formula mass is 203.13. The formula shows that there are 3 ammonium ions in each formula unit. 10.7g/203.13 is 5.27 X 10-2 formula units. Therefore, the number of ammonium ions present in 10.7g of this ammonium phosphate is 3 X 5.27 X 10-2 X Avogadro's Number or 9.52 X 1019 ammonium ions, to the justified number of significant digits.
5/79.02 = .0632 = 6.3%
The formula unit for ammonium sulfide is (NH3)2S. There are 2 nitrogen atoms, 6 hydrogen atoms, and 1 sulfur atom per formula unit. Its molar mass is 66.12g/mol. Mass of Nitrogen = 14.007g/mol x 2 = 28.014g/mol Percent Composition of Nitrogen = (28.014g/mol)/(66.12g/mol) x 100 = 42.37% Mass of Hydrogen = 1.008g/mol x 6 = 6.048g/mol Percent Composition of Hydrogen = (6.048g/mol)/(66.12g/mol) x 100 = 9.147% Mass of Sulfur = 32.06g/mol Percent Composition of Sulfur = (32.06g/mol)/(66.12g/mol) x 100 = 48.49% 42.37% + 9.147% + 48.49% = 100.00%
28.2%