See it's an easy one..!!
AgNO3 + HCl -> AgCl + HNO3
100 mL of 0.068 M AgNO3 contains AgNO3 = 0.068 mol
So,
25 mL of 0.068 M AgNO3 contains AgNO3 = (0.068 * 25) / 1000 = 0.0017 mol
From the equation, we can see
1 mol of AgNO3 gives 1 mol of AgCl
0.0017 mol of AgNO3 gives 0.0017 mol of AgCl
Amount of AgCl can be found this way.!
No. of moles = given mass/ molecular mass
molecular mass of AgCl = 107+35.5 = 143.5 g
Therefore,
Given mass = No. of moles*molecular mass = 0.0017*143.5 = 0.244g
Note : In your question, you have written 0.068 "m" .. (small) m represents for Molality and (capital) M represents for Molarity..!
Hope I helped.. :)
NaI­(aq)­­ + AgNO3(aq) à NaNO3(aq) + AgI(s)
Since the Ksp of AgBr is less than the Ksp of AgNO3, you can predict that the AgBr will precipitate out of solution and leave NO3- in the solution
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the reaction is as follows-AgNO3 + KCl ----->AgCl +KNO3here the silver nitrate(AgNO3) reacts with potassium chloride(KCl) to form potassium nitrate(KNO3) and insoluble AgCl.
A red colouration is obtained. This is a test for ketones
Yes, it is correct.
By definition, No. of moles = given mass/molecular mass; and also by definition, molar concentration of a solute means the number of moles of solute per liter of solution. Therefore, 25 mL of 0.068 M AgNO3 contains AgNO3 = (0.068 * 25) / 1000 = 0.0017 mol of AgNO3.The equation for the reaction is AgNO3 + HCl -> AgCl + HNO3, showing that 0.0017 mol of AgNO3 gives 0.0017 mol of AgCl. The molecular mass of AgCl = 107+35.5 = 143.5 gTherefore, the mass of AgCl produced by the reacion = No. of moles*molecular mass = .0017*143.5 = 0.24g, to the justified number of significant digits.100 mL of 0.068 M AgNO3 contains AgNO3 = 0.068 molSo,Therefore,
AgNO3 (aq) is the formula for aqueous silver nitrate.
The chemical equation is:Fe + 2 AgNO3 = Fe(NO3)2 + 2 Ag
The mass of solid AgBr that is produced when 100.0 ml of 0.150 M AgNO3 is added to 20.0 ml of 1.00 M NaBr 2.82g.
NaI­(aq)­­ + AgNO3(aq) à NaNO3(aq) + AgI(s)
For example silver nitrate: NaCl + AgNO3 = NaNO3 + AgCl(s)
The reaction is:LNaCl + AgNO3 = AgCl + NaNO3The white precipitate is silver chloride.
The reaction is:Cu + AgNO3 = Ag + CuNO3
Since the Ksp of AgBr is less than the Ksp of AgNO3, you can predict that the AgBr will precipitate out of solution and leave NO3- in the solution
When AgNo3 reacts with iodide ions, the precipitate of AgI is formed.AgI is insoluble in HNO3. The symbol of the cation os, I-.
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