Cu + 2AgNO3 ---> Cu(NO3)2 + 2Ag Silver breaks its bond with nitrate and Metallic Copper bonds to the nitrate with Silver changing into its metallic state or 0 charge state.
If the silver nitrate is in aqueous solution and the copper is solid in contact with the solution of silver nitrate, copper atoms will dissolve as ions from the surface of the copper and be replaced by silver atoms formed from the silver ions in solution. This reaction will continue until the entire surface of the copper in contact with the solution is covered with silver. The chemical driving force for this reaction is displacement of one element from its compounds by another element that is higher in the electromotive series than the element displaced.
from what I've seen, if the reaction is being done in distilled water, then the copper attracts the silver nitrate to it and the copper gets a thick film that is very easily removed and leaves tarnished copper looking bright and brand new.
The blue color in the solution is due to the formation of copper(II) nitrate, as the copper turnings react with the silver nitrate solution. This reaction forms copper(II) ions which give the solution a blue color, indicating the presence of these ions in the solution.
A single-displacement reaction occurs where copper replaces silver in the silver nitrate solution to form copper(II) nitrate and solid silver. The blue color of the copper(II) nitrate solution turns a greenish-blue color due to the presence of excess copper ions.
When an iron III nitrate aqueous solution is added to copper, a single displacement reaction occurs where the iron III ions (Fe3+) displace the copper atoms in the solid copper, forming iron II nitrate solution and solid copper III ions. This reaction can be represented by the equation: Fe(NO3)3 + 3Cu → 3Cu(NO3)2 + 2Fe.
A layer of silver will form on the copper metal surface through a displacement reaction, where the copper atoms are replaced by silver atoms in the silver nitrate solution. This reaction is known as a redox reaction, where copper is oxidized and silver is reduced.
first of all which are we talking? Copper (I) Nitrate or Copper (II) Nitrate 2nd, It is an Ionic Solution that will react with any metal except mercury, silver, platinum, and gold.
If the silver nitrate is in aqueous solution and the copper is solid in contact with the solution of silver nitrate, copper atoms will dissolve as ions from the surface of the copper and be replaced by silver atoms formed from the silver ions in solution. This reaction will continue until the entire surface of the copper in contact with the solution is covered with silver. The chemical driving force for this reaction is displacement of one element from its compounds by another element that is higher in the electromotive series than the element displaced.
If a copper spoon is used to stir a solution of aluminum nitrate, a redox reaction may occur between the copper and the aluminum ions in solution. This could lead to the displacement of copper by aluminum, forming aluminum metal on the surface of the copper spoon and changing the composition of the solution.
copper is placed above the silver in the ractivity series which indicates that copper is more reactive than silver . when a copper coin is kept immersed in a solution of siler nitrate ,silver from its solution will deposit on copper coin . copper slowly displaces silver from the silver nitrate solution and the colour of solution changes from colourless to blue due to the formation of copper nitrate . the copper coin will disappear and silver will percipate out .
No, we cannot stir silver nitrate solution with a copper spoon because , copper is more reactive than silver. Thus,it would displace silver from the silver nitrate solution forming copper nitrate....
Copper metal will turn a silver color when placed in silver nitrate solution due to a displacement reaction where silver ions (Ag+) from the solution form solid silver metal on the surface of the copper.
Yes, magnesium reacts with copper nitrate to form magnesium nitrate and copper. The reaction involves the displacement of copper from the copper nitrate solution by magnesium.
When a copper rod is immersed in a silver nitrate solution, a redox reaction occurs where copper displaces silver from the solution to form copper nitrate and silver metal. This is due to copper being higher in the reactivity series than silver. As a result, the copper rod will become coated with a layer of silver metal while copper ions from the rod will transfer into the solution.
If a copper coin is dipped in silver nitrate solution for hours or days, the solution will likely turn blue due to the formation of copper(II) nitrate. This reaction occurs as copper from the coin reacts with the silver nitrate in the solution.
from what I've seen, if the reaction is being done in distilled water, then the copper attracts the silver nitrate to it and the copper gets a thick film that is very easily removed and leaves tarnished copper looking bright and brand new.
The state symbol of copper nitrate solution would be (aq), indicating that it is dissolved in water.