This is a classic electrophilic addition reaction and can be carried out with any of the halogens except fluorine which just explodes and ruins the whole thing!
What's actually happening is that bromine becomes polarised on approach to the hexene double bond due to the pi bond electrons. These 'attack' the positively charged side of the bromine molecule forming a bromonium ion and leaving a negatively charged bromide ion. This then attacks the reverse side of the molecule (because it is easier to access (hindrance) and because the carbon is positvely charged). This forms the final product which is a dibromohexane...
Hope that helps
Richard
Electrons are shared between the chlorine atoms and the bromine atoms.
Cyclopentene + bromine => 1,2-dibromocyclopentane
Hex-1-ene reacts with aqueous bromine in an addition reaction to form 1,2-dibromohexane. During the reaction, bromine adds across the double bond of hex-1-ene to give a product with two bromine atoms on adjacent carbons.
When bromine water is added to ethanol, the bromine will react with the ethanol forming 2-bromoethanol. The reaction occurs via nucleophilic substitution where the bromine reacts with the -OH group of ethanol. This reaction can be used as a test to distinguish between primary, secondary, and tertiary alcohols.
When liquid bromine is shaken with a sodium iodide solution, a redox reaction occurs between the bromine and iodide ions. This reaction results in the formation of brown iodine molecules. The overall reaction can be represented as Br2 + 2NaI → 2NaBr + I2.
When hexene decolourises bromine in carbon tetrachloride, an addition reaction occurs. The double bond in hexene reacts with bromine, resulting in the formation of a vicinal dibromide. This reaction leads to the loss of the characteristic reddish-brown color of bromine, indicating that the bromine has been consumed in the reaction.
The type of reaction that occurs between Hexene and Hydrogen is nothing when the unactivated catalyst is around 100 degrees. When it is between 200 and 300 degrees there is extensive reaction.
Electrons are shared between the chlorine atoms and the bromine atoms.
it goes from a browny orange to colourless
Cyclopentene + bromine => 1,2-dibromocyclopentane
Hex-1-ene reacts with aqueous bromine in an addition reaction to form 1,2-dibromohexane. During the reaction, bromine adds across the double bond of hex-1-ene to give a product with two bromine atoms on adjacent carbons.
When bromine water is added to ethanol, the bromine will react with the ethanol forming 2-bromoethanol. The reaction occurs via nucleophilic substitution where the bromine reacts with the -OH group of ethanol. This reaction can be used as a test to distinguish between primary, secondary, and tertiary alcohols.
When bromine water is shaken with a saturated fat, the orange color of the bromine water will fade due to the reaction between the bromine and the unsaturated fatty acids in the fat. This reaction is a test for the presence of unsaturation in a compound.
When liquid bromine is shaken with a sodium iodide solution, a redox reaction occurs between the bromine and iodide ions. This reaction results in the formation of brown iodine molecules. The overall reaction can be represented as Br2 + 2NaI → 2NaBr + I2.
Bromine water changes from orange to colorless when mixed with unsaturated fats due to the addition reaction that occurs between bromine and the double bonds in the unsaturated fats.
When you mix bromine and sodium, a redox reaction occurs where sodium donates an electron to bromine. This forms sodium bromide, a white crystalline solid, along with releasing a significant amount of heat and light.
The reaction between ethyl cyclohexene and bromine will result in the addition of one bromine atom across the double bond, forming 1,2-dibromoethylcyclohexane. This is an example of electrophilic halogenation of an alkene.