3
potassium hydroxide: KOH you'll need the Ka of it, Ka = [OH-][K+] / [KOH] ; OH and K have the same concentrations, so they're equal, so they can be represented by x. when you have the concentration of OH then you multiply it by -log[OH-], but then you'd have pOH, so just do 14-[-log[OH-]
9L
Perform a acid-base titration with a strong acid with a known concentration. Don't forget to measure the exact mass or the molarity of KOH/K2CO3.Repeat this determination several times to find the right equivalence point, this is important by these kind of quality controls. Then you can calculate the molar ratio of KOH/K2CO3.(V*C)acid = (V*C)base C= concentration and V = volume
use titration formula
2.0 M
347 mL
It will have a basic pH ranging from just above 7 to 14. The precise pH depends on how much of the KOH is in a given volume.
11.91 mL
1) Add 2cm3 of solution to be tested to a test-tube. 2) Add an equal volume of 5% potassium hydroxide* solution and mix. 3) Add 2 drops of 1% copper sulphate solution and mix. A mauve or purple colour develops if protein is present. *Sodium hydroxide solution can be used instead of potassium hydroxide solution.
The first thing you need to do is convert your grams of potassium hydroxide into moles. Potassium hydroxide has the formula KOH. The atomic weights are as follows: K: 39.098 g/mol O: 15.999 g/mol H: 1.0079 g/mol Add them together and you get a formula mass of 56.1049 g/mol. So now divide the mass by this value. 19.9g/56.1049 g/mol = 0.354 mol. Molarity is moles divided by volume. M=n/V Since we are solving for volume we have to rearrange the equation. M*V=n V=n/M So we divide the number of moles by the molarity to get the volume. 0.356 mol/0.55M =0.64 l. So you would need 0.64 liters of water to obtain the desired concentration.
At STP is 2.18L
M = n ÷ V M-Molarity (mol/l) n- moles V- volume in liters. Volume cannot be expressed in grams....
The number of molecules in a given volume of solution depends on the concentration of the solute. Because the concentration is not provided, this question has too little information to answer.
Atomic Volume (cc/mol): 45.3
8.42 grams of KOH is equal to 0.15 moles. If the solution has a molarity of 2.26 moles per liter, then there are 66.4 milliliters of solution.
get the volume of the chemical and the mass and divide the mass by it's volume
First, you must either find or be provided with a known mass of sodium hydroxide and a volumetric vessel. You must also know the molecular mass of sodium hydroxide, which is about 40.00. If the volume of sodium is sufficient, you can complete the preparation by determining the volume of the volume of the vessel in litres, multiply this volume by twice the molecular mass of sodium hydroxide, and dissolve the resulting mass in the known volume.