There is likely no reaction, aniline is a base that upon aquiring a proton converts to a stable ammonium cation, ferric nitrate( Fe(NO3)2 ) has no protons to donate to the amine group of aniline means it will likely not react. In addition the nitrate ion of ferric nitrate is the conjugate base of Nitric acid and is thus extremely stable isn't likely to react with much of anything.
Aniline on heating with Ferric chloride forms Ferric anilide and HCl. 3C6H5-NH2 + FeCl3 = (C6H5-NH)3Fe + 3HCl
When ethyl bromide, an alkyl halide, reacts with alcoholic silver nitrate (AgNO3), silver bromide (AgBr) and ethanol are produced. This reaction is a substitution reaction where the bromine in ethyl bromide is replaced by the nitrate ion from silver nitrate.
Benzoyl chloride reacts with aniline to form N-phenylbenzamide. In the reaction, the chlorine atom of benzoyl chloride is replaced by the amino group of aniline. The reaction is often carried out in the presence of a base to help neutralize the hydrogen chloride byproduct.
Yes, vanillin is positive in a ferric chloride test. When vanillin reacts with ferric chloride, it forms a colored complex that gives a characteristic blue or green color, indicating the presence of phenolic compounds.
The reaction between calcium nitrate and sodium oxalate should produce calcium oxalate as a by-product, along with sodium nitrate. Calcium oxalate is insoluble in water and will precipitate out of solution, while sodium nitrate will remain dissolved.
Aniline on heating with Ferric chloride forms Ferric anilide and HCl. 3C6H5-NH2 + FeCl3 = (C6H5-NH)3Fe + 3HCl
2,4,6-trichloro aniline
Pbl2
Aniline reacts with glacial acetic acid to form N-acetylaniline as the primary product. This reaction involves the acetylation of the amino group of aniline by the acetic acid to form the acetylated product. The reaction is usually carried out in the presence of a catalyst like sulfuric acid to facilitate the acetylation process.
Reaction_of_ferric_chloride_to_sodium_hydroxideBasically: FeCl3 (ferric chloride) + 3NaOH (sodium hydroxide) > Fe(OH)3 + 3NaCl (ferric hydroxide precipitate and sodium chloride, respectively)
Aniline is a chemical compound that can be found in lubricating oils as a degradation product. It is produced when the oil reacts with nitrogen-containing compounds during high-temperature operations. Aniline in lube oil can contribute to the formation of harmful by-products and can negatively impact the oil's performance and longevity.
The reaction of potassium thiocyanate with aniline in the presence of bromine in acetic acid will result in the formation of 2-phenyl-4,5-dihydro-1H-imidazole-1-carbothioamide.
When ethyl bromide, an alkyl halide, reacts with alcoholic silver nitrate (AgNO3), silver bromide (AgBr) and ethanol are produced. This reaction is a substitution reaction where the bromine in ethyl bromide is replaced by the nitrate ion from silver nitrate.
The correct formula for the product of lead(II) nitrate reacting with sodium iodide is lead(II) iodide, which has the formula PbI2. This is because lead(II) ions from lead(II) nitrate react with iodide ions from sodium iodide to form lead(II) iodide as the product.
When sodium reacts with magnesium nitrate, sodium nitrate and magnesium are formed. The balanced chemical equation for this reaction is 2Na + Mg(NO3)2 → 2NaNO3 + Mg.
Aniline reacts with acetic acid to form anilinium acetate salt. The amino group in aniline reacts with the acetic acid to form anilinium ion, and the acetate ion is the conjugate base of acetic acid. This reaction is an acid-base reaction resulting in the formation of a salt.
When iron reacts with air, they form ferric oxide.