Ca(OH)2 = 74.093 g/mol
25g / 74.093 g/mol = 0.3374 mol Ca(OH)2
0.3374 mol / 0.5 mol/L = 0.6748 L Ca(OH)2
which is equal to approximately 675 mL, or 680 rounded up.
To find the volume of calcium hydroxide solution needed to react with the phosphoric acid solution, you need to determine the mole ratio between calcium hydroxide and phosphoric acid. The balanced chemical equation for the reaction will guide you in calculating the amount needed. Once you have the mole ratio, you can use the concentrations and volumes of the solutions to determine the volume of calcium hydroxide needed.
To prepare 6 nM ammonium hydroxide a 30 percent solution you need to know the volume of the 30 percent solution that you have and the volume of 6nM solution you would like to make. Then use the following formula: C1V1 = C2V2 where C = concentration in moles/Liter and V = volume in liters.
The largest volume of 0.100M sodium hydroxide solution would be needed to neutralize a strong acid with a low molarity. This is because a lower molarity acid would require more moles of sodium hydroxide to neutralize it, resulting in a higher volume of the solution being needed.
To find the concentration, we need to calculate the molarity (M) of the solution. First, calculate the molar mass of sodium hydroxide (NaOH) which is 40.00 g/mol. Next, divide the mass of NaOH by its molar mass to get moles. Finally, divide moles by the volume in liters (0.50 L) to find the concentration in moles per liter.
The total volume of the solution is 48 mL + 144 mL = 192 mL. The percent by volume of ethanol is calculated as (volume of ethanol / total volume of solution) * 100%. Plugging in the values, we get (48 mL / 192 mL) * 100% = 25%. So, the solution contains 25% ethanol by volume.
To find the volume of 2.26M potassium hydroxide solution that contains 8.42g of solute, you can use the formula: moles = mass / molar mass. First, calculate the moles of solute using the given mass and molar mass of potassium hydroxide. Then, use the molarity (2.26M) to find the volume of the solution using the formula: volume = moles / molarity.
To determine the volume of potassium hydroxide solution needed to neutralize the hydrochloric acid solution, you can use the formula M1V1 = M2V2. By plugging in the given values, you can calculate the volume of the potassium hydroxide solution required. In this case, the volume of the 0.152 M potassium hydroxide solution needed to neutralize 10.2 ml of the 0.198 M hydrochloric acid solution would be 7.43 ml.
.48 = [OH-]
To find the volume of calcium hydroxide solution needed to react with the phosphoric acid solution, you need to determine the mole ratio between calcium hydroxide and phosphoric acid. The balanced chemical equation for the reaction will guide you in calculating the amount needed. Once you have the mole ratio, you can use the concentrations and volumes of the solutions to determine the volume of calcium hydroxide needed.
To determine the number of grams of pure sodium hydroxide present in a solution with a known volume, you need to know the concentration of the solution in g/ml. Then you can use the formula: grams = concentration (g/ml) x volume (ml)
To prepare 6 nM ammonium hydroxide a 30 percent solution you need to know the volume of the 30 percent solution that you have and the volume of 6nM solution you would like to make. Then use the following formula: C1V1 = C2V2 where C = concentration in moles/Liter and V = volume in liters.
The molarity of the potassium hydroxide solution is 3.30M. This can be calculated by determining the number of moles of sulfuric acid used (0.0171 mol), then equating this to twice the number of moles of potassium hydroxide used (0.00855 mol), and finally dividing this by the volume of the potassium hydroxide solution (0.00258 L).
The largest volume of 0.100M sodium hydroxide solution would be needed to neutralize a strong acid with a low molarity. This is because a lower molarity acid would require more moles of sodium hydroxide to neutralize it, resulting in a higher volume of the solution being needed.
The volume is 1,635 L.
Molarity means moles per litre. So here you have to divide the moles by 75 and multiply by 1000. 0.5/75*1000, which is 6.667 molar.
The ammonium hydroxide solution 28 % has a density of 0,9 g/cm3 at 25 oC.
To find the solubility of carbon dioxide in sodium hydroxide, you can conduct an experiment where you bubble carbon dioxide gas through a solution of sodium hydroxide and measure the amount of carbon dioxide that dissolves in the solution. You can then calculate the solubility of carbon dioxide in sodium hydroxide by dividing the amount of CO2 that dissolves by the volume of the solution.