CaCl2 + Na2HPo4 = @NaCl + CaHPO4
Calcium chloride would be formed from the reaction between hydrochloric acid (HCl) and calcium hydroxide (Ca(OH)2), as hydrogen from the acid combines with the hydroxide from the base to form water, leaving behind calcium and chloride ions that combine to form calcium chloride (CaCl2).
Ca+2 (aq) + C2O4-2 (aq) + H2O (l) --> CaC2O4 *H2O (s)
To make calcium chloride and water, you would react calcium oxide or calcium hydroxide with hydrochloric acid. The reaction would be CaO + 2HCl → CaCl2 + H2O or Ca(OH)2 + 2HCl → CaCl2 + 2H2O.
You should have written CaCl2(aq) + 2AgNO3(aq) → Ca(NO3)2(aq) + 2AgCl(s) (The Precipitation reaction) The full ionic equation though is ............................. Ca2+ + 2Cl- + 2Ag+ + 2NO3- → Ca2+ + 2NO3- + 2AgCl(s)
To find the mass of 0.89 mol of CaCl2, you need to multiply the molar mass of CaCl2 by 0.89 mol. The molar mass of CaCl2 is 110.98 g/mol. Therefore, the mass of 0.89 mol of CaCl2 would be 98.882 g.
There is no equation for reacting CaCl2 and H2O. This is because nothing happens when these two chemicals combine because there is no reaction. If one was to add CaCl2 to H2O, he would end up with wet calcium chloride.
Any reaction occur between these two reactants.
You wouldnt get an oxide. You would get a salt, CO2 and H2O. E.g. CaCO3 + 2HCl ---> CO2 + H2O + CaCl2
When you mix Na2CO3 (sodium carbonate) and CaCl2 (calcium chloride), you would get CaCO3 (calcium carbonate) and NaCl (sodium chloride) as the products in a double displacement reaction. The balanced chemical equation is: Na2CO3 + CaCl2 → CaCO3 + 2NaCl.
Calcium chloride would be formed from the reaction between hydrochloric acid (HCl) and calcium hydroxide (Ca(OH)2), as hydrogen from the acid combines with the hydroxide from the base to form water, leaving behind calcium and chloride ions that combine to form calcium chloride (CaCl2).
Ca+2 (aq) + C2O4-2 (aq) + H2O (l) --> CaC2O4 *H2O (s)
To make calcium chloride and water, you would react calcium oxide or calcium hydroxide with hydrochloric acid. The reaction would be CaO + 2HCl → CaCl2 + H2O or Ca(OH)2 + 2HCl → CaCl2 + 2H2O.
You should have written CaCl2(aq) + 2AgNO3(aq) → Ca(NO3)2(aq) + 2AgCl(s) (The Precipitation reaction) The full ionic equation though is ............................. Ca2+ + 2Cl- + 2Ag+ + 2NO3- → Ca2+ + 2NO3- + 2AgCl(s)
The balanced chemical equation for the reaction between calcium chloride (CaCl2) and sodium stearate (C17H35COONa) would be: 2 CaCl2 + 2 C17H35COONa -> 2 NaCl + Ca(C17H35COO)2 This equation shows that calcium chloride reacts with sodium stearate to produce sodium chloride (NaCl) and calcium stearate.
The product of NaOH and CaCl would be NaCl and Ca(OH)2. The reaction between NaOH and CaCl results in a double displacement reaction where sodium (Na+) exchanges with calcium (Ca2+) to form sodium chloride (NaCl) and calcium hydroxide (Ca(OH)2) as products.
There would be no reaction.
To find the mass of 0.89 mol of CaCl2, you need to multiply the molar mass of CaCl2 by 0.89 mol. The molar mass of CaCl2 is 110.98 g/mol. Therefore, the mass of 0.89 mol of CaCl2 would be 98.882 g.