An alkane will react with the bromine test and become a clear/colourless liquid, while an aromatic hydrocarbon will not react with the bromine and remain a redish-orange tinged liquid.
Since pyrite (a.k.a. fool's gold) and gold have the same color, it can be very difficult to distinguish between them. A very accurate way to distinguish them is by streaks.
This compound doesn't exist.
The compound formed between sodium and selenium is named "sodium selenide" and has the formula Na2Se.
The ionic compound formed between magnesium and chlorine has the formula MgCl2.
No binary compound between beryllium and sodium.
An azocoupling is an organic reaction between a diazonium compound and another aromatic compound which produces an azo compound.
A compound is made up of molecules.
For example the chemical reactivity.
Only one of these occurs naturally.
An element is anything on the table of elements
Huckels rule. 4n + 2 whereby n is any integer for example 1,2,3 etc. Aromatic compounds will obey huckels rule:- (4 x (1)) + 2 = 6 (4 x (2)) + 2 = 10 (4 x (3)) + 2 = 14 Taking benzene as an example...is it aromatic? Is a six membered ring with 3 double bonds, so 6pi electrons thus obeys huckels rule and is aromatic. Negative charges also count as 2pi electrons and positive charges on a molecule are ignored entirely.
A does not burn in air, and B does burn in air.
Heterocyclic compounds may be aromatic (3 double bonds in the cyclic structure) or nonaromatic.
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Aromatic aldehydes are cuter.
how can you distinguish between them
Dissociation in chemistry is the process of splitting of an ionic compound in water solution. Association is the inverse process.