Fluorine.
Assuming that "flourine" is intended to be "fluorine", the answer is no. Both carbon and fluorine are unlikely to be electron donors and therefore form a covalent bond instead, so that both of these non metals can share electrons.
yes, the number of electrons in the outermost shell of the carbon atom is filled with electrons, leaving no electrons unpaired and therefore making it diamagnetic.
Fluorine... by far. Its so electronegative that it will never form double bonds, even if they would make sense by the octet rule. BF3 is a really good example of this
Carbon in the middle with a single bond to fluorine to the left, another single bond with fluorine going down, and a double bond with oxygen to the right. Each fluorine has 3 pairs of electrons on the non-bonded sides. Oxygen has electron pairs on top and bottom.
The reason why fluorine has a higher ionization energy level than oxygen is because it is closer to the nucleus than is oxygen, therefore, it will take more energy to pull electrons from the nucleus.
Fluorine is assinged the oxidation number of -1 because it attracts the electrons in the bond more strongly than the carbon does.
FLourine is the most electronegative element so it likes to grab the electrons from other elements when it is in compounds. If you are comparing two different elements the periodic trend for strong electrnegativity tends to go to the right and up. The trend for the weakest electronegativity goes to the left and down on the periodic table so you could say that Francium is the least electronegative.
The carbon anion, or carbanion, has a lone pair of unbound electrons that give the carbon ion a negative charge....thus being an anion. Being that electrons do not add to the molecular weight of the ion, carbanion would still have a molecular weight of 12 and fluorine of 19. This is assuming that you are referring to the normal isotopes of carbon and fluorine.
yes, the number of electrons in the outermost shell of the carbon atom is filled with electrons, leaving no electrons unpaired and therefore making it diamagnetic.
Assuming that "flourine" is intended to be "fluorine", the answer is no. Both carbon and fluorine are unlikely to be electron donors and therefore form a covalent bond instead, so that both of these non metals can share electrons.
Fluorine... by far. Its so electronegative that it will never form double bonds, even if they would make sense by the octet rule. BF3 is a really good example of this
Carbon to fluorine.
All halogens (fluorine, chlorine, bromine, iodine and astatine) have 7 valence electrons.
fluorine
The electronegativity of carbon on the Pauling scale is 2,55.
The Elements Chlorine Fluorine Carbon
Carbon forms covalent bonds with fluorine.