0
because that tip of the calomel electrode is made up of porous nature..If we keep it in environment, its get oxidised,,
Wiki User
∙ 14y ago
Add your answer:
Earn +20 pts
Why pH probes always kept immersed in 3M Kcl solution?
I just got done talking with a vendor for pH probes and he explained that the KCl solution helps facilitate the measurement of the hydrogen ions with the electrode. It will actually seep out in small quantities from the tip which is a membrane.
Can KCl and CCl4 form a solution?
KCl and CCl4 do they form solution
How many grams of KCl are required to prepare 2.25L of a 0.75m KCl solution?
Molarity = moles of solute/Liters of solution 0.75 M KCl = moles KCl/2.25 Liters = 1.6875 moles KCl (74.55 grams/1 mole KCl) = 126 grams of KCl needed
A solution was prepared by dissolving 40.0 g of KCl in 225 g of water. Calculate the mole fraction of KCl in the solution?
18%
What is the osmolarity of a 0.2M solution of KCL?
0.4
Describe the construction of calomel electrode?
It consists of tube in the bottom of which is a layer of mercury ,over which is placed a paste of Hg+HgCl2.The remaining portion of cell is filled with a solution of normal or decinormal or saturated solution of KCl. a platinum wire dipping into the mercury layer is used for making electrical contact. the side tube is used for electrode is formulated as;Hg,Hg2Cl2,KCl. the electrode can be coupled with the hydrogen electrode of unknown pH.
Why pH probes always kept immersed in 3M Kcl solution?
I just got done talking with a vendor for pH probes and he explained that the KCl solution helps facilitate the measurement of the hydrogen ions with the electrode. It will actually seep out in small quantities from the tip which is a membrane.
How many moles of KCl are contained in 0.635L of 2.2M KCl?
moles KCl = ( M solution ) ( V solution in L )moles KCl = ( 2.2 mol KCl / L solution ) ( 0.635 L of solution )moles KCl = 1.397 moles KCl
Can KCl and CCl4 form a solution?
KCl and CCl4 do they form solution
How many moles of KCl are contained in 1.7L of a 0.83M KCl solution?
moles KCL = ( M solution ) ( L of solution )moles KCl = ( 0.83 mol KCl / L ) ( 1.7 L ) = 1.41 moles KCl
What volume of 0.060 M KCl solution contains 2.39g of KCl?
MW KCl = 74.6 g/mol2.39 gKCl * (1 mol KCL/74.6 g KCl)*(1 L solution/0.06 mol KCL) = 0.534 L
How many moles of KCl are needed to prepare 1.00 L of a 1.0M KCl solution?
M= moles in solution/liters so plug in what you know 3.0M of KCl solution = moles in solution/ 2.0L multiply both sides by 2.0L moles solute = 1.5 moles KCl so you need 1.5 moles KCl to prepare the solution
How will you prepare 3 liters of 2.5 M solution of KCl solution in water?
Dissolve 566.25g of KCl in 3L.
How much 75.66MKCL is required toprepare 1L of solution?
I did not know that you could get a concentration of 75.66 M KCl, but; Molarity = moles of solute/Liters of solution 75.66 M KCl = moles KCl/1 liter = 75.66 moles of KCl 75.66 moles KCl (74.55 grams/1 mole KCl) = 5640 grams KCl that is about 13 pounds of KCl in 1 liter of solution. This is why I think there is something really wrong with this problem!
How many grams of KCl are required to prepare 2.25L of a 0.75m KCl solution?
Molarity = moles of solute/Liters of solution 0.75 M KCl = moles KCl/2.25 Liters = 1.6875 moles KCl (74.55 grams/1 mole KCl) = 126 grams of KCl needed
How much KCL is required for 500mM KCL solution?
0.745*0.5 g
What is the molarity of a solution made by dissolving 4.88 g of KCl in 423 mL of solution?
Need mole KCl first. 4.88 grams KCl (1 mole KCl/74.55 grams) = 0.06546 moles KCl =======================now, Molarity = moles of solute/Liters of solution ( 423 ml = 0.423 Liters ) Molarity = 0.06546 moles KCl/0.423 Liters = 0.155 M KCl ------------------
