Tin Sulphate stays the same during electrolysis because it is low down in the reactivity series, it can only be extracted by the reduction of carbon, not by electrolysis.
Why does the colour of copper sulphate solution change when an iron nail is dipped in it? When an iron nail is placed in a copper sulphate solution, iron displaces copper from copper sulphate solution forming iron sulphate, which is green in colour. Therefore, the blue colour of copper sulphate solution fades and green colour appears.
When an iron nail is placed in a copper sulphate solution, iron displaces copper from copper sulphate solution forming iron sulphate, which is green in colour.Therefore, the blue colour of copper sulphate solution fades and green colour appears.
Silver is lower in the reactivity series than Zinc and therfore cannot displace the Sulphate from the Zinc. But on the other hand zinc is higher than copper, and when displacing the sulphate from the copper it changes colour due to the reaction. Reactivity series(metals): Potassium Sodium Lithium Calcium Magnesium Aluminium Zinc Iron Tin Lead Copper Silver Gold Platinum
The addition of HCl will lead to the formation of HF (hydrogen fluoride) through a reaction between HCl and F- ions present in the solution. This will shift the equilibrium towards the formation of more HF, decreasing the concentration of fluoride ions in the solution.
Adding carbon dioxide to bromothymol blue (BTB) solution causes a color change because it forms carbonic acid, which lowers the pH of the solution. BTB changes color in response to pH changes, shifting from blue in a basic solution to yellow in an acidic solution. The increased acidity due to the carbon dioxide causes the solution to turn yellow.
The concentration of the zinc sulphate solution will not change when a zinc rod is dipped into it. This is because zinc is already present in the solution as zinc ions, so the addition of a zinc rod will not alter the concentration of zinc ions in the solution.
During electrolysis of copper sulfate solution using copper electrodes, the blue color of the solution remains because copper ions from the copper sulfate solution plate onto the cathode, replacing the copper atoms in the electrode. This does not change the color of the solution as the copper ions remain in solution, maintaining the blue color.
Why does the colour of copper sulphate solution change when an iron nail is dipped in it? When an iron nail is placed in a copper sulphate solution, iron displaces copper from copper sulphate solution forming iron sulphate, which is green in colour. Therefore, the blue colour of copper sulphate solution fades and green colour appears.
The concentration of the salt solution does NOT change- it is saturated.
You add zinc to the solution and add 10% of what is left
The conductivity of a solution generally increases as its concentration increases. This is because a higher concentration means there are more ions present in the solution, which allows for better electrical conductivity.
Electrolysis is a chemical change.
The electrical conductivity of the solution will be higher if the concentration of NaCl increase.
A brown layer of copper gets deposited on iron nail. This change is due to a chemical reaction between copper sulphate and iron. Also the colour of the solution changes from blue to green due to the formation of iron sulphate. This reaction can be represented by the following equation: Copper sulphate + Iron = Iron sulphate + Copper solution (CuSO4) + (Fe) = (FeSO) + (Cu)
Concentration.
A change in pH of one unit represents a tenfold change in hydrogen ion concentration. For example, a solution with a pH of 4 has 10 times higher hydrogen ion concentration than a solution with a pH of 5.
In a pharmacy industry, titration is commonly used to determine the concentration of a solution. It involves slowly adding a titrant of known concentration to the solution of unknown concentration until the reaction reaches its endpoint, as indicated by a color change or other observable change. The volume of titrant used is then used to calculate the concentration of the solution being tested.