Because the Nitrogen has five electrons. when it forms a bond with the three hydrogens it has two left over. those two unpaired electron will occupy a non-bonding shell and because of electron replusion, it will want to be as far away from each other as possible. therefore one hydrogen in the plane, one coming out of the paper, one going into the paper and two electrons on top. enjoy
The H-N-H bond angle (assuming that's what the question is trying to ask) is a bit less than the tetrahedral angle, 109.5o.
Ammonium bisulfite is NH4HSO3 Ammonium bisulfide is NH4SH Ammonium bisulfate is NH4HSO4
trigonal planar
Ammonium nitrate is NH4NO3 Ammonium chloride is NH4Cl
ammonium hypophosphate is an ammonium salt of hypophosphoric acid.
Its shape is tetrahedral.
NH4+, or ammonium, has a tetrahedral shape with a covalent bond angle of 109.5 degrees between the hydrogen atoms. The bond length of the nitrogen-hydrogen bond is about 1.04 Angstroms.
It would be angular (V-Shaped)
t-shape.Ax3
A tetrahedral die (not dice!) is a triangle-based pyramid, whose four faces are equilateral triangles.
The H-N-H bond angle (assuming that's what the question is trying to ask) is a bit less than the tetrahedral angle, 109.5o.
No it is not a tetrahedral!
tetrahedral l
Molecular shape is tetrahedral.It has no lone pairs.
SiCl2Br2 would take a tetrahedral shape according to the VSEPR theory.
Since the NH4^+1 ion has 4 H's attached to an N in a tetrahedral shape, it is nonpolar However Ammonia NH3 has 3 H's attached to an N in a pyramidal shape, so it is polar Do a search for Ammonium and ammonia and pick image. You will see the difference.
Any one with a central atom bonded to four others, such as phosphate or ammonium. PO(subscript 4) (superscript 3-) NH(subscript 4) (superscript +)