0
g HCl solution = 2500 mL of HCl * 1 liter/1000 mL * 1190 g/L = 2975 g
37% solution (37 g HCl/100 grams of solution) gives you the grams of HCl:
g HCl = 0.37 * 2975 g = 1100.8 g HCl
Moles HCl = 1100.8/(36.46 g/mole) = 30.2 moles
Therefore the molarity, which equals the normality in this case = 30.2 moles/2.5 L = 12.07 M = 12.07 N
If you want to make 100 mL of a 0.1 N solution,
Volume of HCl solution needed = (0.1 N * 100 mL) /12.07 N = 0.83 mL
Take 0.83 mL of the 37% HCl, and dilute it with water to 100 mL.
What else can I help you with?
What is the normality of commercial grade HCl?
The normality of commercial grade hydrochloric acid (HCl) can vary depending on the concentration specified by the manufacturer. Hydrochloric acid is commonly available in different concentrations, such as 37% or concentrated hydrochloric acid. To determine the normality, it is essential to know the molarity (moles of solute per liter of solution) and the number of equivalents of the acid. Normality (N) is related to molarity (M) by the equation: � = � × � N=n×M where: � N is the normality, � n is the number of equivalents, � M is the molarity. For hydrochloric acid (HCl), which is a monoprotic acid (donates one proton), the number of equivalents ( � n) is equal to 1. Therefore, if you know the molarity of the commercial grade hydrochloric acid, you can determine its normality using the equation mentioned above. It's important to check the product label or contact the manufacturer for the specific concentration of the hydrochloric acid you are using.
How many ml of 6.0 N NaOH is required to neutralize 30 ml of 4 N HCL?
formula for neutralizatrion is volume of acid X normality of acid = volume of base X normality of base so (0.3)(3) should equal (4)(volume) which is .225L. However, Ca(OH)2 contains 2 moles of OH resulting division of total volume needed by 2. Thus, the answer becomes .1125L or 112.5ml.
Difference in the solubality of ciprofloxacin in water and 0.1N HCl solution i-e. I mean to ask that either in water or 0.1 N HCl solution the ciprofloxacin is more soluble?
Ciprofloxacin is more soluble in 0.1 N HCl solution compared to water. The solubility of ciprofloxacin increases in acidic solutions like HCl due to its acidic nature, which helps to increase its solubility in the 0.1 N HCl solution.
Prepare 500ml of 0.12N HCL solution?
To prepare 500ml of 0.12N HCl solution, you will need to dilute a concentrated hydrochloric acid solution. To do this, measure out 2.5ml of concentrated HCl (37% w/w) and dilute it to 500ml with distilled water. Be sure to wear appropriate safety equipment and handle the acid with caution.
What is an N value in soil report?
The N value in a soil report refers to the Standard Penetration Test (SPT) N-value, which is a measure of the resistance of soil to the penetration of a standard sampler driven by a hammer. It is an indicator of the relative density of granular soils and can be used to assess soil strength for geotechnical engineering purposes. A higher N-value typically indicates more dense and stronger soil.
A 25.0 ml sample of hcl was titrated to the endpoint with 15.0 ml of 2.0 normality naoh what was the normality of th hcl what was its molarity?
The normality of HCl can be calculated using the equation: Normality (HCl) * Volume (HCl) = Normality (NaOH) * Volume (NaOH). Solving for the normality of HCl gives 6.0N. The molarity of the HCl solution can be calculated using the formula: Molarity = Normality / n-factor. Assuming the n-factor for HCl is 1, the molarity of the HCl solution would be 6.0 M.
What is lab normality of hcl?
The normality of a solution is a measure of the concentration of a solute in a solution. For HCl (hydrochloric acid), the normality would depend on the concentration of the HCl solution. For example, a 1 M (molar) solution of HCl would be 1 N (normal).
What is the normality of 37 percent fuming HCl?
To find the normality of a solution, you need to know the molarity and whether the solution is monoprotic or polyprotic. Since fuming HCl is typically monoprotic (one hydrogen per molecule), you can assume the normality is equal to the molarity. Therefore, the normality of a 37% fuming HCl solution is approximately 11.1 N (since 37% is roughly 11.1 M HCl).
What is maximum possible normality of HCl?
The maximum possible normality of a solution is limited by the concentration of the solute. For HCl, which is a strong acid, the maximum normality that can be achieved is typically around 12 N. Beyond this concentration, HCl will start to dissociate in multiple steps due to the auto-ionization of water.
What is the normality of commercial grade HCl?
The normality of commercial grade hydrochloric acid (HCl) can vary depending on the concentration specified by the manufacturer. Hydrochloric acid is commonly available in different concentrations, such as 37% or concentrated hydrochloric acid. To determine the normality, it is essential to know the molarity (moles of solute per liter of solution) and the number of equivalents of the acid. Normality (N) is related to molarity (M) by the equation: � = � × � N=n×M where: � N is the normality, � n is the number of equivalents, � M is the molarity. For hydrochloric acid (HCl), which is a monoprotic acid (donates one proton), the number of equivalents ( � n) is equal to 1. Therefore, if you know the molarity of the commercial grade hydrochloric acid, you can determine its normality using the equation mentioned above. It's important to check the product label or contact the manufacturer for the specific concentration of the hydrochloric acid you are using.
What is the normality of one liter solution if it has 3.65 grams of Hydrochloric acid?
Normality is the number of gram equivalents of solute per liter of solution.N = [ ( m ) / ( M ) ( Z ) ] [ 1000 / V in mL ]where Z represents the number of H+ ions that the one molecule of the solute is capableof releasing or reacting with. For HCl, Z = 1 .N = [ ( 3.65 g ) / ( 36.458 g / mol ) ( 1 ) ] [ 1000 mL / 1000 mL )N = 0.100 N
How to prepare 0.2N HCl solution?
0.2 N HCl solution means 0.2 equivalents of HCl dissolved in 1 litre of water. Normality = Molarity x n-factor => Molarity =Normality/n-factor=0.2/1=0.2 M 0.2 moles should be present in 1 litre of solution. 0.2moles =0.2 x 36.5 = 7.3 grams of HCl =>Dissolve 7.3 grams of HCl in 1 litre if water to get a 0.2N solution.
What is the normality if 25mL of 0.5 N NaOH is needed to neuralize 30 mL of the unknown acid solution?
The normality of the unknown acid solution is 0.625 N. This can be calculated by using the equation: Normality of acid x volume of acid = Normality of base x volume of base. Given that 25mL of 0.5 N NaOH neutralizes 30mL of the acid, you can set up the equation and solve for the normality of the acid.
What is the normality of an acid solution if 50 ml of the solution requires 48.6 ml of 0.1879 N alkali for neutralization?
The normality of the acid solution can be calculated using the formula: Normality of acid x Volume of acid = Normality of alkali x Volume of alkali. Plugging in the values, we get: Normality of acid x 50 ml = 0.1879 N x 48.6 ml. Solving for the normality of the acid gives approximately 0.186 N.
What is the unit of normality?
The unit for normality is N, or mol/LN or mol/Lit is the unit
Formula for normality to liquids?
Normality (N) of a liquid solution is calculated by dividing the number of equivalents of solute by the volume of solvent in liters. The formula for normality is N = (equivalents of solute) / (volume of solvent in liters).
Who to calculated normality of iodine?
Normality of iodine ((I_2)) can be calculated using the formula: Normality = Molarity x n, where n is the oxidation state of iodine in the reaction. For example, if you are using a 0.1 M (I_2) solution in a redox reaction where iodine is being reduced to iodide ions ((I^-)), then the normality of iodine would be 0.1 N.
