As oxygen is located in the second period, it has only s and p subshells available. As it has already six electrons, it can gain only two electrons. That means two bonds. Other elements in the same group have d subshell available as well, and it means that they can form more than two bonds.
Yes, technetium can form compounds with other elements due to its ability to exhibit multiple oxidation states. It is known to form a variety of inorganic compounds with elements like oxygen, chlorine, and sulfur. Additionally, technetium can also form coordination complexes with a range of ligands in its +4, +5, +6, and +7 oxidation states.
It is determined from known oxidation states of other elements.
In Mg2P2O7, magnesium (Mg) has an oxidation state of +2, phosphorus (P) has an oxidation state of +5, and oxygen (O) has an oxidation state of -2. The sum of the oxidation states for each element in the compound must equal zero due to its neutrality.
The oxidation state of nitrogen in HNO3 is +5 because oxygen is assigned an oxidation state of -2 and hydrogen is assigned an oxidation state of +1. The sum of the oxidation states must equal the overall charge of the molecule (zero in this case for a neutral compound).
the oxidation states are always 0 for both atoms
Oxygen and sulfur have similar electronegativities, so they tend to share electrons in covalent bonds. This leads to similar oxidation states for both elements in compounds. Oxygen typically has an oxidation state of -2, while sulfur usually has oxidation states of -2, +4, and +6.
Oxidation states of elements in Iodate anion: Iodine = +5 Oxygen = -2
Oxygen can have oxidation states of -2, 0, +1/2, or -1. The most common oxidation state of oxygen is -2, such as in water (H2O) and carbon dioxide (CO2).
Oxygen is the element whose most common oxidation state is -2. In fact, it only shows oxidation states of +2,+1 in compounds OF2, O2F2. It is because oxygen is the second most electronegative element behind Fluorine.
FClO4 is the name of Fluorine perchlorate.Here Chlorine is in +7 oxidation state, Fluorine is in -1 oxidation state, 3 atoms of Oxygen (that are double bonded to Chlorine) are in -2 oxidation state, and the forth Oxygen atom (which is connected to Fluorine and Chlorine) is in 0 oxidation state.So, total charge = 7(of Chlorine) -1(of Fluorine) -(2 * 3)(of 3 Oxygen) +0(of Fourth Oxygen) = 0
Oxygen can have oxidation states of -2, -1, 0, 1, 2 in chemical compounds.
Calcium and Magnesium can become cations with positive oxidation states. Calcium commonly forms Ca2+ ions, while Magnesium typically forms Mg2+ ions. Oxygen and Fluorine are nonmetals and usually gain electrons to form anions with negative oxidation states.
In a compound the sum of oxidation states of the elements contained is zero.E1 + E2 + ... = 0If you know the oxidation states of the elements E1... you can calculate the oxidation state of the element E2.
Predominantly, the transition elements, but also hydrogen, nitrogen, and oxygen. Actually all elements that have reactions can have more than one oxidation number in the sense that their oxidation number is 0 when they are in pure form and usually is some other value when they are in compounds.
In N2O (dinitrogen monoxide or nitrous oxide), the oxidation state of nitrogen (N) is +1 and the oxidation state of oxygen (O) is -2. This is because oxygen typically has an oxidation state of -2 in compounds, and the overall molecule is neutral (zero charge) which means the sum of the oxidation states must equal zero.
Oxygen can have oxidation states of -2 (in most compounds), -1 (in peroxides), 0 (in O2), +1 (in superoxides), and +2 (in compounds like OF2).
the answer is -2.Related Information:The oxidation number of oxygen when it appears as an element is 0. The oxidation number in all compounds but peroxides is -2. The oxidation number of oxygen in peroxides is -1.