Na(1s^2 2s^2 2p66 3s^1) + F(1s^2 2s^2 2s^5) ----> NA+(1s^2 2s^2 2p^6) + F-(1s^2 2s^2 2p^6)
Don't you love E20-20?
The electron configuration of fluoride is 1s^22s^22p^5. This means fluoride has a total of 9 electrons, with 2 electrons in the 1s orbital, 2 electrons in the 2s orbital, and 5 electrons in the 2p orbital.
The element E is likely barium (Ba), as its electron configuration is Kr 5s2. The fluoride compound of barium would be BaF2, with barium losing its two valence electrons to form a 2+ cation and fluoride gaining one electron to form a 1- anion.
An example of a binary ionic compound where both the anion and cation have 10 electrons is lithium fluoride (LiF). Lithium is a cation with 3 electrons, and fluoride is an anion with 9 electrons. When lithium loses an electron and fluoride gains an electron, they form LiF with both having 10 electrons in their outer shells.
Sodium has the electron configuration of neon.
1s2 2s2 2p6 is the electron configuration of the fluoride ion. It has a complete octet and is isoelectronic with neon. Before it becomes an ion, it is 1s2 2s2 2p5 Then it gains an electron and has a negative charge.
The electron configuration of fluoride is 1s^22s^22p^5. This means fluoride has a total of 9 electrons, with 2 electrons in the 1s orbital, 2 electrons in the 2s orbital, and 5 electrons in the 2p orbital.
The element E is likely barium (Ba), as its electron configuration is Kr 5s2. The fluoride compound of barium would be BaF2, with barium losing its two valence electrons to form a 2+ cation and fluoride gaining one electron to form a 1- anion.
The fluoride ion has the same electron configuration as a neon atom. This is because fluoride has gained an extra electron compared to a neutral fluorine atom, resulting in a full valence shell with 8 electrons. Therefore, the electron configuration of a fluoride ion is 1s2 2s2 2p6.
Oh, isn't that just a happy little question! Strontium fluoride has the noble gas electron configuration of krypton, which is [Kr]. This means it has a stable electron configuration similar to a noble gas, making it less likely to react with other elements. Just like painting a serene landscape, understanding electron configurations can bring a sense of peace and harmony to your chemistry studies.
The electron configuration of fluorine is 1s22s22p5. To form the F- ion (fluoride ion), one electron is gained to achieve a full valence shell. Therefore, the missing number of electrons in the electron configuration of F after gaining one electron is 1.
The electron configuration of fluoride ion (F-) is 1s2 2s2 2p6. This is because fluoride gains one electron compared to neutral fluorine, which has the electron configuration 1s2 2s2 2p5.
An example of a binary ionic compound where both the anion and cation have 10 electrons is lithium fluoride (LiF). Lithium is a cation with 3 electrons, and fluoride is an anion with 9 electrons. When lithium loses an electron and fluoride gains an electron, they form LiF with both having 10 electrons in their outer shells.
Fluorine's electron configuration is 1s2 2s2 2p5, and since fluoride is just fluorine with an extra electron, or F-1, its electron configuration is 1s2 2s2 2p6.
The electron configuration for sodium is [Ne] 3s1 and for fluorine is [He] 2s2 2p5. When sodium donates its outer electron to fluorine, sodium becomes Na+ and fluorine becomes F-. The ionic compound formed is sodium fluoride (NaF).
Sodium has the electron configuration of neon.
Sodium fluoride has electron and ionic elements. This is taught in science.
Yes, potassium fluoride forms an ionic bond. Potassium is a metal and fluoride is a non-metal, so they undergo ionic bonding by transferring electrons to achieve a stable electron configuration. In this case, potassium loses an electron to form a positively charged ion (K+) and fluoride gains an electron to form a negatively charged ion (F-), resulting in the formation of an ionic compound.