Write the electron configuration diagram that shows the transfer of electrons that takes place to form the compound sodium fluoride and include the electron configuration of the ions formed?

Answer 1

Na(1s^2 2s^2 2p66 3s^1) + F(1s^2 2s^2 2s^5) ----> NA+(1s^2 2s^2 2p^6) + F-(1s^2 2s^2 2p^6)

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Answer 2

For the formation of sodium fluoride, sodium (Na) will transfer one electron to fluorine (F) to achieve a stable electron configuration. The electron configuration for sodium is [Ne] 3s^1, and for fluorine, it is [He] 2s^2 2p^5. After transfer, sodium forms the Na+ cation with an electron configuration of [Ne], and fluorine forms the F- anion with an electron configuration of [He] 2s^2 2p^6.