The square of the sum of ( x ) and ( y ) is expressed mathematically as ( (x + y)^2 ). This can be expanded using the formula for the square of a binomial, resulting in ( x^2 + 2xy + y^2 ). Thus, the square of the sum of ( x ) and ( y ) captures both the individual squares of ( x ) and ( y ) as well as twice their product.
It is (x + y)^3 - sqrt(5x + 3y) and there is no sensible simplification of this expression.
Twice the sum of 'x' and 'y' . . . 2(x+y) The sum of twice 'x' and 'y' . . . (2x+y)
It can be, it need not be.
2(x+y) is twice the sum of x and y, and 2x+y is the sum of twice x and y
To find the sum of x and y, you simply add the two variables together: sum = x + y. If you have specific values for x and y, you can substitute them into this equation to calculate the sum. Otherwise, the sum remains expressed as x + y.
The sum of x and y decreased by their product is (x + y)- xy.
x+y
Resultant is equal to the square root of the sum of the summation of x-components and the summation of y-components
X+y
5(x^2 + y)
Suppose the numbers are x and y. The sum of their reciprocals = 1/x + 1/y = y/xy + x/xy = (y+x)/xy = (x+y)/xy = 10/30 = 1/3
To find two times the sum of ( x^2 ) and ( y^2 ) increased by three times the sum of ( x^2 ) and ( y^2 ), we first express it mathematically. The sum of ( x^2 ) and ( y^2 ) is ( x^2 + y^2 ). Thus, two times this sum is ( 2(x^2 + y^2) ), and three times it is ( 3(x^2 + y^2) ). Adding these together gives ( 2(x^2 + y^2) + 3(x^2 + y^2) = 5(x^2 + y^2) ).