There is no compound by the formula NaHCO. However, NaHCO3 exists and it is called sodium bicarbonate.
4520 grams
NaHCO doesn't exist; NaHCO3 contain 4 elements.
The formula is NaHCO 3.
Yes Na+ and HCO3- ions
NaHCO(subscript)3
1. Na 2. H 3. C 4. O There are 4.
To neutralize sulfuric acid (H₂SO₄), we first need to determine the moles of H₂SO₄ in the spill. The number of moles is calculated as follows: Moles of H₂SO₄ = Volume (L) × Concentration (M) = 0.024 L × 6.4 mol/L = 0.1536 moles. Since sulfuric acid is a strong acid that can donate two protons, it will react with sodium bicarbonate (NaHCO₃) in a 1:2 ratio. Therefore, we need 0.3072 moles of NaHCO₃. The molar mass of NaHCO₃ is approximately 84 g/mol, so the minimum mass required is: Mass = Moles × Molar Mass = 0.3072 moles × 84 g/mol = 25.77 g. Thus, at least 25.77 g of NaHCO₃ should be added to neutralize the spill.
The presence of Na (Sodium, a metal) and HCO (non metals) make it a bond between a metal and non-metals, thus it is ionic bond.
no it will mess up Club soda contains bicarbonate. Definition of that is: an acid carbonate, as sodium bicarbonate, NaHCO 3 .
Sodium bicarbonate: NaHCO₃ Nickel(III) bromide: NiBr₃ Gold(I) chloride: AuCl Potassium permanganate: KMnO₄
The balanced equation for the reaction between sodium bicarbonate (NaHCO₃) and hydrochloric acid (HCl) is: [ \text{NaHCO}_3 (aq) + \text{HCl} (aq) \rightarrow \text{NaCl} (aq) + \text{H}_2\text{O} (l) + \text{CO}_2 (g) ] From the equation, one mole of sodium bicarbonate reacts with one mole of hydrochloric acid. The molar mass of sodium bicarbonate is approximately 84.01 g/mol, so 4.00 g of NaHCO₃ is about 0.0475 moles. Therefore, it can neutralize an equivalent amount of HCl, which is approximately 1.74 g (using the molar mass of HCl, about 36.46 g/mol).