NaHCO doesn't exist; NaHCO3 contain 4 elements.
NaHCO(subscript)3
NaCl has two elements: sodium (Na) and chlorine (Cl).
Aluminum has 13 elements.
Iodine has 53 elements.
Sulfur has 16 elements.
1. Na 2. H 3. C 4. O There are 4.
There is no compound by the formula NaHCO. However, NaHCO3 exists and it is called sodium bicarbonate.
4520 grams
The formula is NaHCO 3.
Yes Na+ and HCO3- ions
NaHCO(subscript)3
To neutralize sulfuric acid (H₂SO₄), we first need to determine the moles of H₂SO₄ in the spill. The number of moles is calculated as follows: Moles of H₂SO₄ = Volume (L) × Concentration (M) = 0.024 L × 6.4 mol/L = 0.1536 moles. Since sulfuric acid is a strong acid that can donate two protons, it will react with sodium bicarbonate (NaHCO₃) in a 1:2 ratio. Therefore, we need 0.3072 moles of NaHCO₃. The molar mass of NaHCO₃ is approximately 84 g/mol, so the minimum mass required is: Mass = Moles × Molar Mass = 0.3072 moles × 84 g/mol = 25.77 g. Thus, at least 25.77 g of NaHCO₃ should be added to neutralize the spill.
118 elements
There are 118 elements on the periodic table.
92 elements
NaCl has two elements: sodium (Na) and chlorine (Cl).
118 elements