In sodium bicarbonate (NaHCO₃), the oxidation state of carbon (C) can be determined by analyzing the other elements in the compound. Sodium (Na) has an oxidation state of +1, hydrogen (H) is +1, and each oxygen (O) is typically -2. The overall charge of the molecule is neutral (0), so for carbon, we can set up the equation: ( +1 + 1 + x + 3(-2) = 0 ), where ( x ) is the oxidation state of carbon. Solving this, we find that ( x = +4 ). Therefore, the oxidation state of carbon in NaHCO₃ is +4.
C = +2 oxidation state O = -2 oxidation state
In the molecule COH₂ (formaldehyde), the oxidation state of carbon (C) can be determined by considering the oxidation states of hydrogen (H) and oxygen (O). Hydrogen has an oxidation state of +1, and oxygen has an oxidation state of -2. Therefore, for the molecule COH₂, the oxidation state of carbon is calculated as follows: x + 2(+1) + (-2) = 0, which simplifies to x + 2 - 2 = 0, leading to x = 0. Thus, the oxidation state of carbon in COH₂ is 0.
O = -2 oxidation state H = +1 oxidation state
S = +4 oxidation state O = -2 oxidation state
The oxidation state is +3.
+4 oxidation state
The oxidation state of carbon (C) in CO2 is +4. Each oxygen atom in CO2 has an oxidation state of -2, so for the overall molecule to be neutral, carbon must have an oxidation state of +4.
It depends on what form it is in. It can be in the 4+ oxidation state, 4- oxidation state and every oxidation state in between.
C = +2 oxidation state O = -2 oxidation state
There are three elements, carbon, oxygen and hydrogen. Carbon's oxidation number is -4, each hydrogen is +1 and oxygen is +2.
Co = +2 oxidation C = +4 oxidation O = -2 oxidation
The oxidation state of sodium (Na) in Na2C2O4 is +1 because it is an alkali metal. The oxidation state of carbon (C) in C2O4^2- (oxalate ion) is +3.
H=+1 O=-2 To determine oxydation number of C: 2(+1) + 2x + 4(-2)=0 2 + 2x -8 = 0 x = +3 for C
Zinc is in oxidation state +2 and oxygen in oxidation state -2. Zinc Oxide itself has not net charge/oxidation state.
The oxidation number of Ca in CaC2O4 is +2 because Ca, a group 2 element, typically has a +2 oxidation state in compounds. The oxidation number of C in C2O4 is +3 because the overall charge of the oxalate ion is -2, and there are two C atoms, each with an oxidation state of +3 to balance the charge.
The oxidation number for C in NH2CONH2 is +2. This is because each hydrogen has an oxidation number of +1, and oxygen has an oxidation number of -2. By assigning hydrogen and oxygen their usual oxidation numbers, we can determine that the nitrogen atoms in NH2CONH2 have an oxidation state of -3, and since each nitrogen atom contributes three electrons to the carbon atom, the overall oxidation state of carbon is +2.
Here O S of C is -4As,let us take O S of C as xSo, O S of H is +1In CH4 as it is stable so the eq. isx+4(+1)=0or, x = - 4