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In calcium carbide (CaC₂), the oxidation state of calcium (Ca) is +2. Since there are two carbon atoms in the compound and the overall charge must balance to zero, the two carbon atoms must collectively have an oxidation state of -2. Therefore, each carbon atom in CaC₂ has an oxidation state of -1.

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What is oxidation number of c atoms in cac2?

In CaC2, the oxidation number of the Ca atom is +2 because it is a group 2 element. The oxidation number of the C atom is -2 because it typically forms covalent bonds with other elements, resulting in a formal charge of -2 on each C atom in CaC2.


Could you answer what is the oxidation number of ca in cac2?

-1 for Carbon (in carbide) and +2 for Ca


What is the oxidation number for CaC2?

The oxidation number of Ca is 0 in its elemental form and is +2 in its compounds.


What is the chemical formula of calcium carbonide?

CaC2 It is also called Calcium Acetylide which describes the structure better. It forms a chain with a triple bond between the Carbon atoms -Ca-C---C-Ca-C---C-Ca- etc.


What is the oxidation state of c in hc03?

+4 oxidation state


What is the oxidation state of c in CO2.?

The oxidation state of carbon (C) in CO2 is +4. Each oxygen atom in CO2 has an oxidation state of -2, so for the overall molecule to be neutral, carbon must have an oxidation state of +4.


What is the oxidation number of C?

It depends on what form it is in. It can be in the 4+ oxidation state, 4- oxidation state and every oxidation state in between.


What is the oxidation state of COCl2?

C = +2 oxidation state O = -2 oxidation state


What is the oxidation state in each element of COH2?

There are three elements, carbon, oxygen and hydrogen. Carbon's oxidation number is -4, each hydrogen is +1 and oxygen is +2.


The oxidation state of CoCO3?

Co = +2 oxidation C = +4 oxidation O = -2 oxidation


What is the oxidation state of Na2C2O4?

The oxidation state of sodium (Na) in Na2C2O4 is +1 because it is an alkali metal. The oxidation state of carbon (C) in C2O4^2- (oxalate ion) is +3.


What is the oxidation state of each element in h2c2o4?

H=+1 O=-2 To determine oxydation number of C: 2(+1) + 2x + 4(-2)=0 2 + 2x -8 = 0 x = +3 for C

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