In the molecule COH₂ (formaldehyde), the oxidation state of carbon (C) can be determined by considering the oxidation states of hydrogen (H) and oxygen (O). Hydrogen has an oxidation state of +1, and oxygen has an oxidation state of -2. Therefore, for the molecule COH₂, the oxidation state of carbon is calculated as follows: x + 2(+1) + (-2) = 0, which simplifies to x + 2 - 2 = 0, leading to x = 0. Thus, the oxidation state of carbon in COH₂ is 0.
O = -2 oxidation state H = +1 oxidation state
S = +4 oxidation state O = -2 oxidation state
The oxidation state is +3.
The oxidation state of F in HOF (hydrogen monofluoride) is -1. Hydrogen is typically assigned an oxidation state of +1, leaving the fluorine with an oxidation state of -1.
C = +2 oxidation state O = -2 oxidation state
There are three elements, carbon, oxygen and hydrogen. Carbon's oxidation number is -4, each hydrogen is +1 and oxygen is +2.
Following the IUPAC definition method (typically taught in the US) O is with few exceptions -2 , H is +1 in this instance (it is only -1 when linked to a reactive metal). Therefore as the overall oxidation state of the molecule is zero as it is uncharged the oxidation number of C is 0. Other answers are possible as there are other ways to work it out a previous contributor offered this answer:- To get the oxidation number for COH2 can be calculated by adding the oxidation of the individual elements. COH2 C is (+4), 2H is (-2) and O is (-2) which equals to 0.
Trigonal Planar
The oxidation state of chloride (Cl) is -1. As a halogen, chloride is usually found with an oxidation state of -1 in most compounds.
The oxidation state of calcium is +2.
The oxidation state of carbon in methanol (CH3OH) is +2. This is because oxygen has an oxidation state of -2 and hydrogen has an oxidation state of +1, so the carbon must have an oxidation state of +2 to balance the charges in the molecule.
2 oxidation state
O = -2 oxidation state H = +1 oxidation state
The oxidation state of calcium in calcium hydride is +2, as calcium typically forms ionic compounds with a +2 oxidation state.
S = +4 oxidation state O = -2 oxidation state
Platinum is connected to two anionic Chloride ligands and two neutral Ammine ligands Platinum = +2 oxidation state Chlorine = -1 oxidation state Nitrogen = -3 oxidation state Hydrogen = +1 oxidation state
Zinc is in oxidation state +2 and oxygen in oxidation state -2. Zinc Oxide itself has not net charge/oxidation state.