Following the IUPAC definition method (typically taught in the US) O is with few exceptions -2 , H is +1 in this instance (it is only -1 when linked to a reactive metal). Therefore as the overall oxidation state of the molecule is zero as it is uncharged the oxidation number of C is 0.
Other answers are possible as there are other ways to work it out
a previous contributor offered this answer:-
To get the oxidation number for COH2 can be calculated by adding the oxidation of the individual elements. COH2 C is (+4), 2H is (-2) and O is (-2) which equals to 0.
The oxidation number of acetate (CH3COO-) is -1. The carbon atom has an oxidation number of +3, each hydrogen atom has an oxidation number of +1, and the oxygen atoms have an oxidation number of -2.
The oxidation number of each hydrogen in H2CO2 is +1, while the oxidation number of each carbon in CO2 is +4. This is because hydrogen usually has an oxidation number of +1, and oxygen usually has an oxidation number of -2.
The oxidation number of nitrosyl (NO) is +1. Nitrogen typically has an oxidation number of -3, and oxygen typically has an oxidation number of -2. In NO, nitrogen has a -3 oxidation number and oxygen has a -2 oxidation number, leading to an overall oxidation number of +1 for the nitrosyl ion.
Oxidation number of Nb is +4. Oxidation number of O is -2.
The oxidation number for H is +1, and the oxidation number for O is -1.
There are three elements, carbon, oxygen and hydrogen. Carbon's oxidation number is -4, each hydrogen is +1 and oxygen is +2.
In the molecule COH₂ (formaldehyde), the oxidation state of carbon (C) can be determined by considering the oxidation states of hydrogen (H) and oxygen (O). Hydrogen has an oxidation state of +1, and oxygen has an oxidation state of -2. Therefore, for the molecule COH₂, the oxidation state of carbon is calculated as follows: x + 2(+1) + (-2) = 0, which simplifies to x + 2 - 2 = 0, leading to x = 0. Thus, the oxidation state of carbon in COH₂ is 0.
Trigonal Planar
For HClO oxidation No. is '0' . It is a neutrally charged molecule. However, The chlorine atom is in oxidation state (+1). How so???? you may ask . Using oxygen as that standard at '-2' , and hydrogen at '+1' We create a little sum +1 + Cl -2 = 0 ( overall charge on the molecule). Collecting terms Cl - 1 = 0 Cl = + 1 as required. NB When dissolved in water chlorine disproportionates. That is it simultaneously oxidises and reduces., Cl2(aq) = Cl^(+)(aq) + Cl^(-)(aq) It reacts with water molecules to form ;- Cl2 + H2O = HClO + HCl The supply of drinking water from public sources has chlorine bubbled through to act as a bacteriocide (kill the bugs). So tap/faucet water is a very weak solution of hydrochloric acid(HCl) and Hydrogen chlorate(bleach)(HClO). It won't harm you, because the solution is so weak, but just enough to kill the bugs.
The oxidation number of acetate (CH3COO-) is -1. The carbon atom has an oxidation number of +3, each hydrogen atom has an oxidation number of +1, and the oxygen atoms have an oxidation number of -2.
The oxidation number of each hydrogen in H2CO2 is +1, while the oxidation number of each carbon in CO2 is +4. This is because hydrogen usually has an oxidation number of +1, and oxygen usually has an oxidation number of -2.
Silicon's oxidation number is +4.Oxygen's oxidation number is -2
The oxidation number of nitrosyl (NO) is +1. Nitrogen typically has an oxidation number of -3, and oxygen typically has an oxidation number of -2. In NO, nitrogen has a -3 oxidation number and oxygen has a -2 oxidation number, leading to an overall oxidation number of +1 for the nitrosyl ion.
Oxidation number of Nb is +4. Oxidation number of O is -2.
MnCl2: oxidation number +2MnO2: oxidation number +4KMnO4: oxidation number +7
The oxidation number for H is +1, and the oxidation number for O is -1.
The oxidation number of H in HNO2 is +1, the oxidation number of N is +3, and the oxidation number of O is -2.