Assuming that the question is referring to India's national engineering entrance exam, JEE Main or previously know as Indian Institute of Technology - Joint Entrance Exam, 165 cutoff would place the person in top rank 20,000 out of 150,000. This should enable the said student to sit for the subsequent JEE Advanced, for a chance of admission into the coveted Indian Institute of Technology or National Institute of Technology.
Numbers 3.5 and 11. The numbers are actually prime factors of 165 (165=3*5*11).
1 university, 1 community college, 216 public schools.
It comes out tonight. You can watch it right here the moment it comes out subbed: http://www.animecrazy.net/2008/03/18/bleach-episode-165/
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The GCF is 165.
165% of 20 = 165% * 20 = 1.65 * 20 = 33
50% of 165 = 50% * 165 = 0.5 * 165 = 82.5
85*165/100 = 140.2585*165/100 = 140.2585*165/100 = 140.2585*165/100 = 140.25
the answer to 165 divided to 165 is 15
It is 165, exactly as it appears in the question.
90% of 165 pounds= 90% * 165= 0.9 * 165= 148.5 pounds
Since 165 is a factor of 330, it is automatically the GCF.