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What else can I help you with?
How do you get a gate pass for ADM?
kindly issue RGP in transformer 5KVA from Cheema Boiler ltd
Is 5kva the same as 50hz?
No. 5Kva is a power rating, standing for 5 kilovolt/Amps, 5,000 v/a. This is how much a generator or tranformer can handle or output. 50Hz is the frequency of an A/C waveform, power supply, generally used in the UK and influenced countries. 50 cycles per second.
Price of 5kva diesel generator in tamilnadu?
pls telme 3phase 7.5kwe enerater pric 10 hp g
What will be cable rating for 5kva 3phase system?
It depends on the voltage: 208 v 14 amps, 415 v 7 amps, 480 v 6 amps.
How much current will 5 kva ups draws while charging?
- For a single phase supply @ 220 voltscurrent drawn by 5kva UPS = 22.7 amperes (at full load.)
What will be the full load current of single phase 5Kva ups?
Assuming single phase voltage 220 Volts AC, the maximum current would be approximately 25 amps.
What is the fuel consumption of 5 kva generator?
if your generator fuel consumtion is 275g/kwh, then you multipli 5kva*.8=4kw. (4*275)/1000=1.1 liter per hour.
How many watts for 5kva?
Max 5 kW but it could be less for certain types of load, for example a motor. Most motors have a power factor of less than 1 . . . . 0.8 for example, which would give 4 kW from 5 kVA.
How many turns does a transformer need to take 137V on the primary and produce 47V on the secondary with output current of 20A for a 5kVA stabilizer?
You will need a 3:1 ratio transformer. An output current of 20 amps and a secondary voltage of 47 volts, results in a transformer rated at 940 VA.
How many 100amp hour batteries do you need to connect to a 240v inverter to produce the same output as a 5kva generator for a period of 2 hours?
I am assuming that your batteries are 12V, also that your (12V - 240V) inverter is rated for 5KW output and it is about 95% efficient. Most big inverters are between 85% - 97%. 5KW from a 12V battery would mean a current draw of about 416A, but since the inverter is only 95% efficient the actual current would be closer to 438A. If you draw 438A for two hours, that's 876AH. Theoretically then, you would need 9 100AH batteries. The problem is that at very high current draw, all batteries AH capacity is less than the rating. You only get the whole 100AH if the current draw is 10A (1/10th the AH rating) or less. Because of that, you would probably need 10 to 12 batteries. If you used 10 batteries, each would source about 44A during full load. You would have to use very large bus bars to equalize the current draw from battery to battery. If the interconnects are too small, the batteries closer to the inverter would be forced to supply more than their equal share of the total current draw, and the ones further away less. It's generally problematic to parallel large numbers of batteries in this way. Don't even consider it unless the batteries are identical (same manufacturer, same part number, same age, same date code). The problem gets even worse when you try to recharge the pack. Suppose you pump 50A of charging current into 10 batteries. Is each battery receiving 5A? Or is one battery with a shorted cell drawing all 50 (and is about to explode...)? There's no way to tell. Even if all batteries were receiving equal charge, it would take your 50A charger almost 40 hours to recharge 10 - 100AH batteries. Ouch. Large industrial UPS systems get around this by using huge 2V cells in series. You can buy 6 - 2V, 1000AH cells, connect them in series to form a 12V, 1000AH battery and avoid all the hassles of parallelling 12V, 100AH batteries. They are not cheap, though. If you go to a battery manufacturer's website, they publish graphs for their batteries that show AH derating versus current draw. All this assumes, of course, that your load is really 5KW. If you are running a smaller load, then obviously your battery count would go down. Finally, we are talking extremely large current and power levels here. If you are not fully qualified to understand and design high current wiring systems, don't try this! 400A of current through a bad connection can do serious damage! Unless you enjoy being sprayed with molten metal from a disintegrating connection, know what you're doing or get a qualified individual to help with/inspect your work. IF YOU ARE NOT ALREADY SURE YOU CAN DO THIS JOBSAFELY AND COMPETENTLYREFER THIS WORK TO QUALIFIED PROFESSIONALS. If you do this work yourself, always turn off the powerat the breaker box/fuse panel BEFORE you attempt to do any workANDalways use an electricians test meter having metal-tipped probes(not a simple proximity voltage indicator)to insure the circuit is, in fact, de-energized.
How many 100amp hour batteries do you need to connect to a 96VDC inverter to produce the same output as a 5kva generator for a period of 8 hours?
We can only do this in a sketchy way, because some important numbers are missing.-- You didn't mention the voltage of the 100-AH batteries.-- We don't know whether the inverter can deliver 5,000 watts, like the generator can.-- We also don't know the efficiency of the inverter.So we'll go at it in terms of the total energy, we'll assume that the inverter can dowhatever we want it to do, and at the end, we can toss in a term for its efficiency.-- At the back end, you specified 5 KVA for 8 hours. If the generator is 100% loaded,with a power factor of 100%, then that's (5 x 8) = 40 KWH of energy in 8 hours.-- If the inverter is 100% efficient, then 40 KWH is what the batteries need to supply, in 8 hours.-- I'm going to assume that your batteries are the nominal-12-VDC "car battery" type.So you need 8 of them in series to power the 96-VDC inverter.-- The batteries keel over and die after delivering 100 Amp-Hours. At 96 volts,that's 9,600 watt-hours of energy.-- Throughout the 8 hours, you need 40,000 watt-hours. One string of batteriesdelivers 9,600. That's 24% of the total energy required. Instead of 24%, I want towrite it as 6/25 of the total energy. You'll see why in the next line . . .-- Since the one 96-volt string of 8 batteries produced 6/25 of the required total energy,you need 25/6 = 4.1666 strings, in parallel.You have to supply the batteries in sets of 96 volts, in order to run the inverter.So far, the answer is 41/6 96-volt strings.We assumed that a 100-AH battery could actually deliver 100-AH, and the voltagewould never sag. Realistically, you shouldn't count on more than maybe 90% of that.Call that number the "battery margin".We assumed that the inverter is 100% efficient ... all of the energy that comesout of the batteries shows up at the inverter's output. That never happens. There'salways some energy lost in the inverter. I'm going to call the efficiency of theinverter ' E '. It's a percent, it's less than 100, and I'll leave it up to you to find out.So, here's the best I can do: You asked for the number of batteries.-- Number of batteries in each series string = 96/battery voltage .For 12-V car batteries, it's 8 batteries in each string.Each battery assumed to be rated 100-AH.-- Number of strings:(41,666) divided by [ (battery margin percent) times ( ' E ' percent) ]========================Example:Battery margin = 90%Inverter efficiency = 80%Number of strings = (41,666)/[90 x 80] = 41,666/7,200 = 5.79 . . . Use 6 strings.RED FLAG . . .This whole discussion assumes that the inverter is rated for 5,000 watts output or more. If it's not, then this has been an interesting exercise, but please forget the whole idea.Your inverter CANNOT match the output of a 5 KVA generator for more than about 10 seconds.After that, it'll be the clickety-clack of tripped breakers, echoing through the smoke.
How many W is 5Kva?
kVA means thousands of VA. For DC, a VA (volt times ampere) is really a watt. For AC, it may be a watt, but it may also be a bit less, depending on the power factor. The power factor takes into account the fact that voltage and current may be slightly out of phase. However, for most practical applications the power factor is usually close to one.
