Answer:
Capacitance is unaffected by frequency; it does not change.
Details:
Capacitance is unaffected by frequency. In a capacitor, what increases with Frequency is Admittance (analogus to Conductance) .
The capacitive Reactance is inversely proportional to Frequency. Therefore, when Frequency is increased, current flow may increase.
you have it reversed. capacitance increases with decrease in distance of plates.
The capacitive reactance of a capacitor increases as the frequency decreases.
Yes. Increasing the plate area of a capacitor increases the capacitance. The equation of a simple plate capacitor is ...C = ere0(A/D)... where C is capacitance, er is dielectric constant (about 1, for a vacuum), e0 is electric constant (about 8.854 x 10-12 F m-1), A is area of overlap, and D is distance between the plates. (This is only a good estimate if D is small in comparison to A.) Looking at this, you can see that capacitance is proportional to plate area.
The charging and discharge time increases. R*C=T
A practical amplifier will contain several components of a "shunt" capacitance inherent in the transistor and physical wiring of the amplifier circuit. As the frequency of the input signal increases, the reactance of these shunt-capacitances will decrease until, at a frequency determined by the value of the shunt-capacitance and the circuit impedance, signal attenuation begins to take place. Thus the shunt capacitances limit the high-frequency response of the amplifier (note that the transistor itself also has inherent limits to it's high frequency amplifying capability). In the case of operational amplifiers, many operational amplifiers are internally compensated by a small capacitor (e.g. about 30pf for a 741). The internal frequency compensation capacitor prevents the operational amplifier from oscillating with resistive feedback.
you have it reversed. capacitance increases with decrease in distance of plates.
Definitely not possible. Capacitance is given by an expression C = epsilon x A / d Since charge is not present the capacitance cannot be increased or decreased by the charge placed
The relationship between potential difference and capacitance in a capacitor is that the potential difference across a capacitor is directly proportional to its capacitance. This means that as the capacitance of a capacitor increases, the potential difference across it also increases, and vice versa.
The electric field strength in a parallel plate capacitor is directly proportional to the capacitance of the capacitor. This means that as the capacitance increases, the electric field strength also increases.
In an electrical circuit, voltage is directly proportional to charge and inversely proportional to capacitance. This means that as the voltage increases, the charge stored in the capacitor also increases, while capacitance decreases. Conversely, if capacitance increases, the voltage across the capacitor decreases for a given charge.
Capacitors have an equivalent reactance of 1/jwC (ohms) where w is the angular frequency of the AC signal and C is the capacitance. As the frequency of the signal across the capacitor increases, the capacitor reactance approaches 0 (capacitor acts like a short circuit). As the frequency of the signal across the capacitor decreases, the capacitor reactance approaches infinity (capacitor acts like an open circuit). So, if you have a high frequency signal (like a step input) the capacitor will momentarily act like a short.
Inserting a dielectric other than air or vacuum between the plates of a capacitor increases the capacitance of the capacitor. The dielectric material increases the electric field strength within the capacitor, which enhances its ability to store charge. This results in a higher capacitance value compared to having air or vacuum between the plates.
When frequency increases, the energy of the radiation increases. Additionally, the pitch of sound also increases with frequency. In electrical circuits, the impedance of a capacitor or inductor also increases with frequency.
Capacitive reactance (expressed in ohms) is inversely-proportional to the supply frequency, so it will decrease when the frequency increases. The following equation applies:XC = 1/(2 pi f C)where:XC = capacitive reactance, in ohmsf = frequency, in hertzC = capacitance, in farads
The capacitive reactance of a capacitor increases as the frequency decreases.
When a dielectric is inserted between the plates of a capacitor, it increases the capacitance of the capacitor. This is because the dielectric material reduces the electric field between the plates, allowing more charge to be stored on the plates for a given voltage.
Capacitance is a measure of how much charge a capacitor can store for a given voltage. As the voltage across a capacitor increases, the capacitance typically remains constant. However, in some cases, the capacitance may change slightly due to factors like dielectric breakdown or non-linear effects.