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Total supply voltage = 220v

rated power of first lamp= 100 watt

so current though it, I=p/v

I=100/220=.45 amps

Resistance offered by first lamp=220/.45= 488 ohms( i avoid fractions)

..............................................................

rated power of second lamp=60 watts

voltage is same, so current through it = 60/220=.27 amps

resistance of second lamp = 220/.27=814 ohms( i avoid fractions)

.........................................................................

power drawn by first lamp =I12 R

=(.45)2 * 488 =98.82(=100)

power drawn by second lamp =I22 R

=(.27)2 * 814 =59(=60)

...................................................................................

SO 100 WATT BULB WILL GROW BRIGHTER AS IT HAS MORE POWER

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Q: 100w bulb and 60w bulb connected in parallel to 220v which will glow brightly?
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