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A 5 uf capacitor has 5x10 coulombs a charge stored in its plates find the voltage across the capacitor?
Q=CV, with Q=(5x10) = 50 Coulombs, and C=5x10^-6 Farads,
therefore: 50 = 5x10^-6 x V
V = 50 / (5x10^-6) = 10,000,000 Volts.
Seems like rather a lot! Maybe there's a typo in the question? Either way, use Q=CV to give the right answer.
is this right seems rather high to (50 volts?)
What else can I help you with?
A 1000 uF capacitor hold 9.2 coulombs of charge what is the voltage on the capacitor?
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A microfarad measures electrical capacitance. A farad can be defined as the charge in coulombs, which is 1 ampere per second, that a capacitor will accept for the potential across it to charge one volt. A microfarad is equal to one millionth of a farad.
Why do resistor voltage decrease while capacitor discharges?
The reason why resistor voltage decreases while a capacitor discharges is because the resistor acts like a source of electrical energy. As the capacitor discharges, it draws energy from the resistor, which causes the voltage across the resistor to decrease. This is because the capacitor is acting like a drain, and is taking energy out of the resistor, thus causing the voltage across the resistor to decrease. The resistor and capacitor work together in order to create a discharge circuit. This is done by connecting the capacitor to the resistor, and then to a voltage source. The voltage source supplies the energy to the resistor, and then the resistor transfers this energy to the capacitor. As the capacitor discharges, it takes energy from the resistor, which causes the voltage across the resistor to decrease. In order to understand this process better, it is important to understand the basics of Ohm's Law. Ohm's Law states that the voltage across a resistor is equal to the current through the resistor multiplied by the resistance. As the capacitor discharges, it takes energy from the resistor, which means that the current through the resistor decreases, and therefore the voltage across the resistor will also decrease.
Why power rating of capacitor is reactive in nature?
A capacitor is composed of metal plates. Voltage is applied to one, which causes electrons to build up on the other. This is reactive in nature, thus a capacitor is reactive. It stores a charge, and releases this charge when the voltage decreases.
How capacitor used in a timing circuit?
A capacitor relies on the time it takes for the voltage across it to reach a certain value. When it is fully discharged, it acts like a piece of copper wire. ie: it conducts. The voltage across it now is zero. When a voltage is applied to it, it begins to charge, and so the voltage measured across it's terminals increases. This takes time. How much time depends on the voltage applied resistor connected to it and the value of the capacitor.This voltage is then used to energies a relay, turn a transistor on, fire an SCR, and lots of other things.
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In order to double the voltage across a capacitor, you need to stuff twice as much charge into it.
How do you charge a capacitor?
You charge a capacitor by placing DC voltage across its terminal leads. Make sure when using a polarized capacitor to place positive voltage across the positive lead (the longer lead) and negative voltage across the negative lead. Also make sure that the voltage you charge the capacitor to doesn't exceeds its voltage rating.
A 1000 uF capacitor hold 9.2 coulombs of charge what is the voltage on the capacitor?
9200 volts my 1000 uF capacitor only holds 10 volts
What is the relationship between the voltage drop across capacitors and the amount of charge stored in them?
The voltage drop across a capacitor is directly proportional to the amount of charge stored in it. This means that as the charge stored in a capacitor increases, the voltage drop across it also increases.
How can one determine the process of finding the charge on a capacitor?
To determine the charge on a capacitor, you can use the formula Q CV, where Q is the charge, C is the capacitance of the capacitor, and V is the voltage across the capacitor. By measuring the capacitance and voltage, you can calculate the charge on the capacitor using this formula.
What is the formula for calculating the charge stored in a capacitor?
The formula for calculating the charge stored in a capacitor is Q CV, where Q represents the charge stored in the capacitor, C is the capacitance of the capacitor, and V is the voltage across the capacitor.
Will voltage drop across a capacitor?
basically a capacitor will charge to the input DC level however it will mathematically never happen since capacitors charge at a certain rate the voltage drop across a capacitor will follow the R C time constant or 63% of the applied voltage for a unit time.AnswerIn the case of an a.c. supply, yes, there will be a voltage drop across a capacitor. In the case of an 'ideal' capacitor, this will be the product of the load current and the capacitive reactance of the capacitor.
How can we calculate the charge on each capacitor in the circuit?
To calculate the charge on each capacitor in the circuit, you can use the formula Q CV, where Q is the charge, C is the capacitance of the capacitor, and V is the voltage across the capacitor. Simply plug in the values for capacitance and voltage for each capacitor in the circuit to find the charge on each one.
What is the method to find the charge on each capacitor in a circuit?
To find the charge on each capacitor in a circuit, you can use the formula Q CV, where Q is the charge, C is the capacitance of the capacitor, and V is the voltage across the capacitor.
What happens to a capacitance if the plates have a charge that is doubled?
The capacitance won't change, or it won't change significantly. The capacitance is simply the charge/voltage ratio - and if the charge doubles, the voltage will also double. Capacitance is determined by the physical properties of the capacitor (plate separation, plate area, and dielectric). The unit for capacitance (farad) is a coulomb per volt. So the capacitance is the amount of charge (coulombs) that the plates will hold at a given voltage.
What is the formula to calculate the maximum charge on a capacitor in an electrical circuit?
The formula to calculate the maximum charge on a capacitor in an electrical circuit is Q CV, where Q represents the charge on the capacitor, C is the capacitance of the capacitor, and V is the voltage across the capacitor.
