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The answer is NO.
Ohm's law states that current (I) flowing through the conductor is proportional to the potential difference (V) developed across its ends, keeping physical conditions such as pressure, temperature, strain constant.
In a filament lamp, the heating element used is Tungsten (W) which has high melting point and resistivity. Due to which , when current passes through it gets heated up and glows producing light and heat. As more and more, current flows through it, it gets considerably heated, resulting in increase of temperature. This is against the requisite condition "constant temperature". Hence Ohm's law cannot be verified using filament lamp because the temperature varies when the current flows through it.
What else can I help you with?
What is meant by cold resistance of filament lamp?
It means exactly what it sounds like. The resistance of an incandescent bulb's filament depends on its temperature. A filament has a positive temperature coefficient, which means that its resistance increases as its temperature increases. A typical 40 watt bulb (120 volts) has a cold resistance of about 28 ohms, but its hot, operating resistance is about 360 ohms. If the cold resistance were constant, the bulb would dissipate 379 watts. In fact, cold turn on is the most stressful time for a bulb.
What is the resistance of an electric lamp that takes in a current of 0.40 ampere when 110 volts is applied?
Ohm's Law: Resistance is voltage divided by current 110 volts divided by 0.4 amperes is 275 ohms.
Why do the reading differ for increasing and decreasing values of the lamp voltages?
at the time of decreasing lamp voltage as the temperature is already high the gas in the lamp is already in ionized state leading to different resistance ,but when increasing voltage the gas is not in ionized state it ready to ionize ,so there is slightly variation in resistance . :)
What must know to calculate current using Ohms law?
The resistance R in ohms (Ω) is equal to the voltage V in volts (V) divided by the current I in amps (A)
How much current flows through a lamp with a resistance of 60 Ohms when the voltage across the lamp is 12 V?
The relation between resistance R, Current I and voltage V is: R= V/I Therefore: 60 = 12 / I <=> I = 12 / 60 = 0.2 amp
If the tungsten filament of a lamp has a cross-sectional are of 5x10-9 m2 how long must it be have a resistance of 120 ohms at 20 degrees Celsius?
To find the length of the tungsten filament, you can use the formula: R = ρ * (L/A) Where R is the resistance (120 ohms), ρ is the resistivity of tungsten, A is the cross-sectional area (5x10^-9 m^2), and L is the length of the filament. Rearranging the formula to solve for L gives: L = R * A / ρ Given the resistivity of tungsten at 20 degrees Celsius, you can calculate the length of the filament.
What happen if a 110 volt lamp connected on a low voltage?
If you had a 60 watt incandescent bulb it would draw about 1/2 amp. That means that the resistance of the bulb filament would be about 220 ohms. Now if you applied 12 volts DC across 220 ohms you would draw about .05 amps. This would not be enough to heat the filament and create any useful light. Remember Ohm's Law says Volts = Amps x Ohms.
What is meant by cold resistance of filament lamp?
It means exactly what it sounds like. The resistance of an incandescent bulb's filament depends on its temperature. A filament has a positive temperature coefficient, which means that its resistance increases as its temperature increases. A typical 40 watt bulb (120 volts) has a cold resistance of about 28 ohms, but its hot, operating resistance is about 360 ohms. If the cold resistance were constant, the bulb would dissipate 379 watts. In fact, cold turn on is the most stressful time for a bulb.
What is the resistance of a domestic filament lamp?
Voltage squared equals current times resistance, so voltage squared divided by power equals resistance. So, for a 60W bulb: * (120V)^2 / 60 = R * 14400 / 60 = 240 ohms Keep in mind this is after the bulb reaches operating temperature. The resistance of the filament is temperature dependent.
Why does the filament lamp does not follow Ohms Law give any example?
Well, honey, the filament lamp doesn't give a hoot about Ohm's Law because its resistance changes with temperature. As the current increases, the temperature of the filament rises, causing the resistance to also increase. It's like trying to control a wild horse - good luck getting it to follow any law!
What is the resistance of an electric lamp that takes in a current of 0.40 ampere when 110 volts is applied?
Ohm's Law: Resistance is voltage divided by current 110 volts divided by 0.4 amperes is 275 ohms.
What difficulty will Aries while testing wheather the filament of light bulb obeys ohms law?
If you plot a graph of current against a range of voltages applied to an incandescent lamp, the result will be a curvedline. This tells us that the current is not proportional to the voltage and, so, the lamp does not obey Ohm's Law.However, the ratio of voltage to current will indicate the resistance for that particular ratio.
What is the resistance of 150-volt lamp with a current of 2amps?
75 ohms. R = E/I.
Can you use a 24 volt lamp in a 12 volt socket?
Let's say you have a 60 watt bulb. At 120 VAC that bulb will draw 1/2 amp. By Ohm's Law: Volts = Current x Resistance. Therefore, the resistance of the bulb filament is 240 Ohms. If 12 volts is applied across 240 Ohms the current = 12/240 or 1/20 of an amp. This small current will not be sufficient to heat up the filament and provide useful light. You might see a small glow in a dark room.
What is 12040000000000 in ohms using a metric prefix?
12.04 Ter-Ohms
Why do the reading differ for increasing and decreasing values of the lamp voltages?
at the time of decreasing lamp voltage as the temperature is already high the gas in the lamp is already in ionized state leading to different resistance ,but when increasing voltage the gas is not in ionized state it ready to ionize ,so there is slightly variation in resistance . :)
How do you find OHM?
Ohms can be found by using these formulas. Ohms = Volts/Amps, Ohms = (Volts (squared))/Watts, Ohms = Watts/(Amps (squared)).
