0
How much current flows through a lamp with a resistance of 60 Ohms when the voltage across the lamp is 12 V?
Wiki User
∙ 12y ago
The relation between resistance R, Current I and voltage V is:
R= V/I
Therefore: 60 = 12 / I <=> I = 12 / 60 = 0.2 amp
Wiki User
∙ 12y ago
Add your answer:
Earn +20 pts
Why does higher resistance have a larger voltage drop across it?
In a d.c. circuit, voltage drop is the product of resistance and current through that resistance.
How does voltage and resistance behave in a series and a parallel circuit?
The current through each resistor is equal to the voltage across it divided by its resistance for series and parallel circuits.
Voltage across resistor is doubled the current is?
Ohm's law states that the voltage across a resistor is the product of the current times the Resistance or V=I x R (I times R). V is Voltage, R is Resistance, and I is Current or Amperage. So if the Voltage is doubled and Resistance stays the same, the Current will be doubled.
Ac voltage applied across a load resistance produce alternating current?
The reason an AC voltage applied across a load resistance produces alternating current is because when you have AC voltage you have to have AC current. If DC voltage is applied, DC current is produced.
What is difference between ideal current source and practical current source?
Internal resistance. The ideal current source has no internal resistance in parallel with it (if it was set to supply no current it would act as an open circuit), and all the current it supplied would have to flow through its load (even if the load was an open circuit, in which case the voltage across the current source would be infinite). A real current source has the practical limitation that it must have an internal resistance in parallel with it, therefor some of the current it supplied is bypassed through that internal resistance and never reaches the load (if the load was an open circuit, then all the current supplied is bypassed and the resulting voltage drop across the internal resistance limits the voltage across the current source).
Why does higher resistance have a larger voltage drop across it?
In a d.c. circuit, voltage drop is the product of resistance and current through that resistance.
What is the current drop across the resistor?
The correct question is what is the voltage drop across a resistor or the current flowing through the resistor using Ohm's Law where Voltage = Current x Resistance
What are those different power ratings for the same resistance?
The amount of current that will pass through a resistance is dependant upon the voltage applied across the resistance. Voltage devided by resistance equals current. This is Ohm's Law.
If a circuit has a resistance of 4 ohm's how much voltage is needed to produce a 1.4 current in the circuit?
Voltage across a resistance = (resistance) x (current through the resistance) =4 x 1.4 = 5.6If the ' 1.4 ' is Amperes of current, then the required voltage is 5.6 volts.
What is the current through a 1.5k resistor with voltage of 3V across it?
Two milliamperes. Ohm's law: Current equals voltage divided by resistance.
What is the rule for voltage across each resistor?
Volt across a resistor = resistance x current through the resistor.
What is a IR drop across a resistance?
IR drop across a resistance is voltage. The letter I means current, and the letter R means resistance. Current times resistance, by Ohm's law is voltage.
How does voltage and resistance behave in a series and a parallel circuit?
The current through each resistor is equal to the voltage across it divided by its resistance for series and parallel circuits.
What is the relationship between voltage and MA?
The "current" through any conductor is voltage across the conductor/conductor's resistance .The current is measured in "Amperes" (amps)."MA" stands for "Milliamps". There are 1,000 of those in one whole ampere.So, the current through a conductor is1,000 times the voltage across the conductor/conductor's resistance . . . in MA
What limits the current that flows through a circuit for a particular appllied DC voltage?
The voltage applied and the resistance across it.
What is an equation for power?
Power = (energy used)/(time to use it)Power dissipated by an electrical circuit =(voltage across the circuit) x (current through the circuit)or(resistance of the circuit) x (square of the current through the circuit)or(square of the voltage across the circuit)/(resistance of the circuit)
How calculate unknown resistance?
-- Connect a source of known, small voltage across the ends of the unknown resistance. -- Measure the resulting current through the unknown resistance. -- Divide (small known voltage)/(measured current). The quotient is the formerly unknown resistance.
