Two diodes, whether or not discreet, cannot work together as a transistor. The diodes and transistor have different profiles to optimize them for their specific functions
No because we need a small base but by connecting two didoes back to back we can not get a small base
A: an operational amplifier has two input A+ and a - input feeding to a base of a transistor ideally both diodes are matched with a current source to make them equal so basically they are both balanced or virtually at the same potential increasing one potential to one will inversely effect the other. usually these junctions are transistor base to emitter but it could that one is just a plain diode working on the exponential curve of the diodes
This question does not make sense.
because in ce configuration value of input voltage requried to make the transistor on is very less value of the output voltage or output current
These diodes are used in a variety of applications from low power radar systems to alarms. A major drawback of using IMPATT diodes is the high level of phase noise they generate. This results from the statistical nature of the avalanche process. Nevertheless these diodes make excellent microwave generators for many applications. A main advantage is their high power capability. They operate at frequencies between about 3 and 100 GHz or more. http://artizle.blogspot.com
Enormously! The predecessor to the transistor was the valve (tube in America). The valve was fragile, ran very hot, physically large and expensive to make. The transistor (although initially expensive) is robust, efficient, tiny and practically free nowadays (a modern Intel processor contains over 500 million transistor and costs around £100 so a transistor costs 20 millionths of a penny). So the change to the world has been the possibility of cheap "intelligent" electronics being added to many aspects of life.
When investigated with an ohm-meter, a transistor resembles two diodes connected "back-to-back". But you can't make a transistor by connecting two diodes back-to-back.
No, it is not possible because in transistor the depletion layers formed in Emitter-Base Junction & Collector-Base Junction are penetrable by both current carriers but in this case of two diodes; the formed depletion region are not penetrable for current carriers (hole &electron). Also, a transistor works only because the base layer is very thin. You won't get that thin layer between emitter and collector just by connecting two diodes together. This thin base layer places the Emitter and Collector in very close proximity to each other. This allows majority carriers from the emitter to diffuse as minority carriers through the base into the depletion region of the base-collector junction, where the strong electric field collects them. In other words the emitter/base current flow draws some of the barrier charge away from the collector/base junction and allows collector/emitter current to flow across the base using minority carriers. So transistor action is not possible. But we can make transistor by connecting two diodes and two dependent current sources i.e. Ebers-Moll model of transistor. This is true only when you want to make the transistor act like a on/off switch, but you cannot make this setup of diodes to act like an amplifier. Whereas the transistor also acts as an amplifier too A transistor can act as: (1) on/off switch (2) amplifier. Diode is made up of two layers and one junction. Transistor is made up of three layers and two junctions.
Yes, if the transformer output is center-tapped; otherwise, no, a bridge rectifier requires four diodes, or six for three phase power. More technically correct, what we are talking about is a full-wave rectifier. A bridge rectifier is properly always four or six diodes.
A: an operational amplifier has two input A+ and a - input feeding to a base of a transistor ideally both diodes are matched with a current source to make them equal so basically they are both balanced or virtually at the same potential increasing one potential to one will inversely effect the other. usually these junctions are transistor base to emitter but it could that one is just a plain diode working on the exponential curve of the diodes
A diode allows current to pass in one direction only, and has two pins - Anode and Cathode. A transistor is a switch that has three pins - Collector, Base, Emitter, and a current can pass between the collector and emitter if there is a current on the base. A picture of diodes and transistors can be found here (left to right: diode, transistor, transistor, LED - diode that lights up): http://www.mediafire.com/imageview.php?quickkey=zmwz5and0lm&thumb=6
This question does not make sense.
You can use a transistor as a diode if you connect the base to the collector. Any forward current through the base-emitter junction would cause a corresponding increase in the available current through the collector-emitter junction. Since the base-emitter and collector-emitter junctions are in parallel, this would effectively be a diode, but a true diode would be a better solution if diode functionality is what seek. A: There are actually two diodes, per se, inside a transistor. The base to emitter diode will suffice. By tying the collector to the base it will in effect be two diodes in parallel.
The metalloids is combined in transistor radios to make them of high quality.
No.Di, or bi, means two. A diode, from the Greek di (two), and ode (path), has, rather obviously, two connections, which, in older ones (valves/thermionic diodes), were called electrodes.A transistor has three connections (so it would make, at least grammatic, sense to call it a triode).
Though germanium diodes were the first ones fabricated, several factors make silicon the choice vs. germanium diodes. Silicon diodes have a greater ease of processing, lower cost, greater power handling, less leakage and more stable temperature characteristics than germanium diodes. Germanium diodes' lower forward drop (.2V to .3V versus .7V to 1.0V) make them better at small signal detection and rectification.
As I have no information on the circuit I can make no valid predictions as to the effect of replacing diodes with resistors. However I assume the effect(s) will resemble that of having very defective diodes in the circuit.
They make them in many different places.