It does not matter, since the ohmmeter needs to be connected to the device in isolated mode. Series or parallel; they are both the same, in this case.
No, the total resistance increases.
The voltage (or 'potential') coil has the higher resistance, because it is connected in parallel with the load.
Load current is related to load resistance by an inverse relationship. The load current increases linearly as load resistance decreases. Remember, the less resistance, the more current.
There is no such thing as 'resistance across' a load! The correct term is 'resistance of a load'.To answer your question, it depends on how the loads are connected. If they are connected in series, for example, the total resistance is equal to the sum of the individual resistances. If they are connected in parallel, then you must use the following equation: 1/R = 1/R1 + 1/R2 + 1/R3 + etc.For any other connection, you will have to work it out individually.
Internal resistance. The ideal current source has no internal resistance in parallel with it (if it was set to supply no current it would act as an open circuit), and all the current it supplied would have to flow through its load (even if the load was an open circuit, in which case the voltage across the current source would be infinite). A real current source has the practical limitation that it must have an internal resistance in parallel with it, therefor some of the current it supplied is bypassed through that internal resistance and never reaches the load (if the load was an open circuit, then all the current supplied is bypassed and the resulting voltage drop across the internal resistance limits the voltage across the current source).
You almost NEVER do. 1) The circuit should be off and/or disconnected when using an ohmmeter. 2) It should be in parallel with the component as far as the rest of the circuit is concerned, but alone in series with the device its measuring.
Because an ohmmeter works by putting a potential difference (voltage) across a load and measuring the resulting current (the current will be inversely proportionate to the resistance). In a live circuit there is already current flowing through the load so (at best) the reading will be inaccurate, at worst the meter will be damaged.
Parralel
No, the total resistance increases.
The typical ohmmeter measures DC resistance by providing DC current and measuring the voltage drop accross the resistor. By definition, the 'ideal' capacitor is an open circuit to DC current and voltage. By definition, an open circuit has infinite resistance. Of course, real-world capacitors are not ideal. They have a very high parallel leakage resistance and a very small series resistance. And, different meters can measure different ranges of resistance. So, you may not get an infinite/overload measurement on some capacitors with some meters. You may get a very high resistance instead. If so, you are not really measuring the resistance of the 'capacitor', but rather that of the imperfections in the component manufactured to be a capacitor. ANSWER: The ohmmeter battery will charge the capacitor in 5 time RC after that it quirts there is no more current flow. Any body that claim to be able to check resistance of a capacitor i just a wannabe
The voltage (or 'potential') coil has the higher resistance, because it is connected in parallel with the load.
You measure it indirectly using a known load resistance and measuring supplied current. Loading of the ammeter should be known as well, and the load resistance should be made relatively small to get accurate results.
This happens because the total parallel resistance is lower than the individual resistors that make up the group of parallel resistors. When you add another parallel load, the resistance of that parallel group lowers and as result increases the current for the rest of the circuit.
A: An ammeter actually is a voltmeter measuring the voltage drop across a very small shunt resistance. They can measure AC or DC, make sure the meter is rated for the anticipated current, and always connect in series.
If a 'parallel' circuit has more than one load in its (not "it's"!) branches, then it is not a parallel circuit, but a series-parallel circuit! To resolve the circuit, you must first resolve the total resistance of the loads within each branch.
Ohm's Law says Voltage = Current x Resistance With constant voltage, an increase in resistance decreases the current. Now the load can be added in two basic ways. If the load is added in series the resistance will increase. If you add load in parallel the resistance will decrease and the current will increase from the source.
if the resistance of the meter is low that will act as a parallel load effecting the reading. If the meter can be made with infinite resistance then the meter will not effects the actual reading.