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For a sinusoidal waveorm, RMS (effective, heating) value = 2/pi x (peak voltage).

It's not 2/pi for waveforms with other shapes.

2/pi = roughly 63.7%

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12y ago

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What is the instantaneous voltage of 90 degrees?

The instantaneous voltage at 90 degrees in a sinusoidal waveform is at its peak value, as this angle corresponds to the maximum point of the sine function. Mathematically, if the voltage is represented as ( V(t) = V_{\text{max}} \sin(\omega t + \phi) ), at 90 degrees (or ( \frac{\pi}{2} ) radians), the voltage is ( V(t) = V_{\text{max}} ). Thus, the instantaneous voltage is equal to the maximum amplitude of the waveform.


What is the voltage at 90 degrees if the instantaneous voltage is 225v at 60 degree angle?

To find the voltage at 90 degrees given an instantaneous voltage of 225 V at a 60-degree angle, we can assume a sinusoidal function for the voltage. The voltage can be represented as ( V(t) = V_m \sin(\theta) ), where ( V_m ) is the maximum voltage. Since you provided the instantaneous voltage at 60 degrees, you can calculate the maximum voltage ( V_m ) using ( V_m = \frac{225}{\sin(60^\circ)} ). Then, to find the voltage at 90 degrees, you would evaluate ( V(t) ) at that angle, resulting in ( V(90^\circ) = V_m \sin(90^\circ) = V_m ).


What is powerful mean?

The product of the instantaneous voltage and the instantaneous current for a circuit or component.


What is the relationship between voltage and current in a pure inductive?

In a pure inductive circuit, the voltage and current are out of phase by 90 degrees. This means that the current lags the voltage, with the maximum voltage occurring a quarter cycle before the maximum current. As a result, the current reaches its peak value after the voltage, leading to a relationship where the instantaneous current is proportional to the rate of change of the voltage. Overall, this phase difference highlights the reactive nature of inductors in an AC circuit.


How do you get effective or rms voltage?

To calculate the effective (RMS) voltage of an AC signal, you can use the formula ( V_{\text{RMS}} = \frac{V_{\text{peak}}}{\sqrt{2}} ) for a sinusoidal waveform, where ( V_{\text{peak}} ) is the maximum voltage. For non-sinusoidal waveforms, the RMS voltage can be obtained by taking the square root of the average of the squares of the instantaneous voltages over one complete cycle, expressed mathematically as ( V_{\text{RMS}} = \sqrt{\frac{1}{T} \int_0^T v(t)^2 , dt} ), where ( T ) is the period of the waveform. This calculation provides a measure of the effective voltage that delivers the same power as a DC voltage.


Solving problems on instantaneous voltage and current?

yes


What is alternative voltage?

Alternating voltage is the E.M.F. and is one whose magnitude whose magnitude changes with time and direction reverses periodically. The instantaneous value is given by E=Eo sin w t, where,E=value of alternating voltage at time t Eo = maximum value of alternating voltage(amplitude) w=angular frequency of supply.


Maximum generating voltage in world?

maximum generated voltage is 21KV


What is the instantaneous voltage of a sine wave at 25 degrees if its peak voltage is 30 V?

12.68V 3o * sin25 = 12.67854785


What is the relation between amperage and capacitance?

The relationship between amperage and capacitance is indirect. Capacitance stores and releases electrical energy, affecting the flow of current in a circuit. Higher capacitance can lead to slower changes in current (i.e., lower frequency), while lower capacitance can result in faster changes in current.


What is the formula for instantaneous current?

The formula for instantaneous current (i) in a circuit is given by Ohm's law: i = V / R, where V is the voltage across the circuit and R is the resistance.


What is instantaneous power mean?

Instantaneous power refers to the power being consumed or generated at a specific moment in time. It is calculated as the product of the voltage and current at an exact instant and represents the rate at which energy is being transferred or converted at that particular point. It is commonly used in electrical engineering to analyze dynamic power consumption in circuits or systems.

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