By definition, MVA is equivalent to the vector sum of MW and MVAR: MVA^2 = MW^2 + MVAR^2 = 2500 MVA = 50
mw is the unit of real power and mvar is unit of reactive power. You should now the current and power factor angle to calculate the voltage.p=vi cos piq=vi sin piAnswerI think you mean MW, not mw -capital 'M' mega; lower-case 'm' milli!!! And the symbol for watt is a capital 'W', not a lower case 'w'. Also, I think you mean 'Mvar'(mega, not milli!).
As you have written it (mvar), it stands for 'reactive millivolt amperes', but I think you probably mean 'Mvar', which stands for 'reactive megavolt amperes'. These are units for reactive power of an alternating-current load.A lower-case 'm' represents 'milli', whereas an upper-case 'M' represents 'mega'. 'V' represents 'volts', 'A' represents 'amperes', and 'r' represents 'reactive'.SI does not specify a symbol for reactive volt amperes (it only recognises 'watts'), so it is seen in written in various ways, including: var, VAR, VAr, VA(r), and VAr -in each case, it is also common to see a 'raised period' between the V and the A -e.g. V.Ar .
Q = 3 Vph Iph sin(phase angle) = 31/2 Vline Iline sin(phase angle)
1mva = 1000kva so you simply divide by 1000. 10000KVA = 10MVA K = kilo = 1000 M = mega = 1000000
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By definition, MVA is equivalent to the vector sum of MW and MVAR: MVA^2 = MW^2 + MVAR^2 = 2500 MVA = 50
mw/mva=power factor reactive power(Q)=I2XL or E2/XL where XL= REACTANCE apparent power = square root of (MW2 + MVAR2 )
For 230 kv application, Its around 75k/MVar
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