By definition, MVA is equivalent to the vector sum of MW and MVAR:
MVA^2 = MW^2 + MVAR^2 = 2500
MVA = 50
Multiply the vots by the amps to find the volt-amps. Or divide the volt-amps by the voltage to find the amps.
Amps is amps be it DC or AC.
There are 20 million amps or 20,000,000 amps.
In 50 VA the V stands for volts and the A is for amps. Hence the formula you are looking for is 50/240 = Amps.
5 amps
800 000 Watts / 600 Volts = 1333.3333333 Amps
There are zero volts in 910 megawatts. Watts are the product of amps times volts.
Watts = Volts x Amps. 12 megawatts = 12,000,000 watts. You need to know current to calculate the voltage.
You have to know the current carring capacity of the line and the power factor to make the calculation. Watts = Amps x Volts x p.f If p.f is unity, then watt = Amps x Volts
101 amps for chassis wiring and 37 amps for power transmission. This is for short lengths of wire.
High power transmission lines carry several hundred amperes up to 2000 amps at voltages up to 500 kV or higher
The equation you need to find amperage when kilowatts are known. Amps = kW x 1000/1.73 x volts x PF. Use .9 as a Power Factor constant.First megawatts must be changed to kilowatts. 1000000/1000 = 1000 kilowatts. Amps = 1000 x 1000/ 1.73 x 480 x .9 = 1000000/747 = 1338.6 amps.
Maximum amps for chassis wiring : 101 amps Maximum amps for power transmission : 37 amps Reference : http://www.powerstream.com/Wire_Size.htm
The maximum amperage it can carry for power transmission is .92 amps.
A #8 copper wire with an insulation rating of 90 degrees C is rated at 45 amps.
55 <<>> A #6 copper conductor with an insulation factor of 75 or 90 degrees C are both rated for 65 amps.
You mean MW (megawatts) not mw (milliwatts). If it is generating 200 MW, that is 200,000,000 watts, at 25,000 volts, the current is given by watts/volts = 8000 amps.