Multiply the vots by the amps to find the volt-amps. Or divide the volt-amps by the voltage to find the amps.
The formula for amps is I = W/E. Amps = 40/240 = .17 primary amperage. For the secondary amperage I = W/E. Amps = 40/24 = 1.7 amps.
Watts= voltage times amps. So if you divide Watts by voltage, you will get amps = .33333 or about a 1/3 amp load. This is assuming a 120 volt circuit.
55/12=4.6
It is drawing .06 amps.
It would be at least 250 amps, maybe 300 amps.
The formula for amps is I = W/E. Amps = 40/240 = .17 primary amperage. For the secondary amperage I = W/E. Amps = 40/24 = 1.7 amps.
That depends on circuit voltage. 1 watt is equal to 1 volt times 1 amp.
Depends on the battery. It is listed on the battery as Cold Cranking Amps (CCA).
50
2.083 amps
62.5 amps
Watts= voltage times amps. So if you divide Watts by voltage, you will get amps = .33333 or about a 1/3 amp load. This is assuming a 120 volt circuit.
watts = volts * amps--> Amps = watts/ volts therefore; 2000/220= 9.09 amps
at 240/50 volt itequates to 4amp
55/12=4.6
It is drawing .06 amps.
It is 40 volt-amps, which is 40 volts at 1 amp, or 10 volts at 4 amps, etc. On an AC supply it could be equal also to 40 watts, or some lesser number of watts depending on the power factor of the load.