The input voltage (primary) and output (secondary) of a transformer is determined by the manufacturer. Transformers are bought to accommodate the voltage that is needed on the primary side and to what voltage is needed on the secondary side.
depending on the amount of the load of transformer as well as the power factor of it, there is a transformer specific voltage drop at its terminals, due to the internal impedances. The on-load tap changer can / will be used to compensate this voltage drop or rise.
Tis question is incompleet.1000 va =1 kva.This is the power capacity of transformer. A transformer having 2 currents Primary current and secondary current . for that we required both voltage. Simply we can calculate by a formula Voltage x Current x 0.8(power factor)=1000.
The ratings state the limits on voltage and current for operating the transformer at full load. The rated voltage times the rated current gives the rated VA of the transformer. Transormers are not usually rated directly for power because this depends on the power factor of the load applied.
for given power,High voltage transformer requires more insulation in window from phase to phase and phase to core.Amount of insulation in window increases and net copper area will decrease,Window space factor=(Net copper area in window/window area)Kw = Ac/AwHence, with increase in voltage rating,net copper area decreases and ultimately window space factor reduces.
As long as the voltage insulation factor of the conductors are the same and they are of the same circuit fed by the primary side of the transformer's disconnect switch then yes the two feeders can be run together. It is not usually done though because the transformers feeders usually start at an MCC or splitter of one voltage and the load side of the transformer usually goes to a distribution point of some sort at a different voltage.
depending on the amount of the load of transformer as well as the power factor of it, there is a transformer specific voltage drop at its terminals, due to the internal impedances. The on-load tap changer can / will be used to compensate this voltage drop or rise.
Tis question is incompleet.1000 va =1 kva.This is the power capacity of transformer. A transformer having 2 currents Primary current and secondary current . for that we required both voltage. Simply we can calculate by a formula Voltage x Current x 0.8(power factor)=1000.
zero volatge regulation means the terminal volatge of transformer at full load on a given power factor become equal to the rated teriminal volatge of transformer , it happens only for leading power factor in transformer
Compare a transformer to a balancing act. Both side need to remain equal.The primary side of the transformer is the supply side and the load is connected to the secondary side of the transformer.The load governs the current of the secondary side of the transformer and the voltage of the secondary side must match the voltage that the load required to operate.The ratio of the transformer will determine what the voltage of the secondary side is as compared to the voltage that has to be applied to the primary.The current of a step up transformer will be higher on the primary side that that of the secondary.Apply voltage and current to this concept and you will see that the transformer will remain balanced.The size of the transformer is always calculated from the secondary side of the transformer and the value is written in VA or KVA where V = voltage and A = amperage. Power factor is also taken into consideration when calculating the size of the transformer to be used.
With varying power factor the load current drawn changes, which in turn affects the voltage regulation
The ratings state the limits on voltage and current for operating the transformer at full load. The rated voltage times the rated current gives the rated VA of the transformer. Transormers are not usually rated directly for power because this depends on the power factor of the load applied.
Transformers voltage ratings are typically at full load. For instance, A 24 VAC, 10A transformer will have a terminal voltage of 24 when it is feeding 10 amps to a load. Since the transformer windings have some resistance, the transformer designer has to wind the transformer to put out more than 24 volts, since some of the voltage will be lost, dropped across the resistance of the secondary windings. But, according to Ohm's law, the voltage dropped across a resistance is proportional to the current (E=IR). If we take away the 10A load, there is no current, and therefore no winding voltage drop! The excess voltage the designer built in now appears at the terminals. This is the no-load voltage. In my example above, when we remove the 10A load, the output voltage of the transformer might rise to 26.4V. We would say the no-load voltage of that transformer is 26.4V The ratio of full-load voltage to no-load voltage is called the transformer's "regulation factor". It is calculated as: (no-load voltage - full-load voltage) / full-load voltage * 100. Ours is: ((26.4 - 24) / 24) * 100 = 10%.
kw of 100kva=100*0.8 pf=80kw( if the power factor is 0.8)
copper loss is directly propostional to I (AMPERE) and iron loss directly propostional to V (VOLTAGE) then total losses is equal to volt ampere hence the rating of transformer in KVA. SULTAN
Power is normally transmitted at high voltage through step up/step down transformers to minimize the power losses in the transmission lines (this is one reason anyway). Since power loss is equivalent to the resistance of the conductor times the current squared, stepping up the voltage by a factor of two cuts the transmission losses by a factor of (2^2 = ) 4.
In an ideal transformer, if the voltage is stepped up by a factor of x, then the current is stepped down by a factor of x. The end result is that the power, P=VI, is not changed. Again, this is in the ideal case.
for given power,High voltage transformer requires more insulation in window from phase to phase and phase to core.Amount of insulation in window increases and net copper area will decrease,Window space factor=(Net copper area in window/window area)Kw = Ac/AwHence, with increase in voltage rating,net copper area decreases and ultimately window space factor reduces.