Summation of individual load connected on the board gives the total load.
Power (Load ) = Voltage x rated current.
well the difference mainly exists in the method of finding them , these are :-1. in finding DC load line :-open all AC sourcesopen all the capacitors2. for AC load line:-open all the Dc sourcesshort all the capacitors.
yes.it is possible to start dc series generator on no load condition
when the dc supply given, dc load line lies in the Ic and Vcc. when the AC supply given, AC load line lies in the Ic and Vcc.
heavy load
load test on dc shunt generator is a test to plot the internal and external characteristics of the generator.
DC Current divided by 1.225
for DC load and if its copper wire the cross section of the conductor wire is generally calculated as 1/4 th of the current rating . Eg for a DC load of 16 amp the copper conductor with 4 mm square is selected.
well the difference mainly exists in the method of finding them , these are :-1. in finding DC load line :-open all AC sourcesopen all the capacitors2. for AC load line:-open all the Dc sourcesshort all the capacitors.
Copper is not something that is calculated. The amount of copper might be, or copper losses / load losses, might be, but "copper" is not calculated.
yes.it is possible to start dc series generator on no load condition
when the dc supply given, dc load line lies in the Ic and Vcc. when the AC supply given, AC load line lies in the Ic and Vcc.
A dc load line is formed by joining the 2 points wherin the slope is equal to the inverse of the load resistance.. whereas the ac load lin has a different slope... and it intersects the dc load line at the quiescent point.
heavy load
There are three formulas to calculate current. They are I = E/R, I = W/E and I = the sq. root of W/R. As you can see there is one value missing in your question so it can not be answered.
I am not an electrical guy....but since this question was left unanswered....i'll just put in some nonsense!! For AC Load: VxIxPF (V=VoltageRequired, I=Current Required, PF=Power Factor) The Power Factor is normally considered to be 0.8 as a thumb rule. For DC Load: VxI, here the power factor is consisdered to be 1, since it is a DC current !! Byeee!
A: A transistor has voltage gain as base current is allow to flow. If the load is constant then a DC mirror azimuth path can be plotted as a function of base current and collector current and that is the load line
It depends on the total load of the transistor as to what the shape of the slope is for the DC load line. A transistor gains voltage as base current is allowed to flow.