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What you may be referring to, since the question was posted in electrical engineering section, is in reference to the electrical switches and devices installed on sprinkler systems. The systems have water flow devices, low air switches, valve tamper devices and the like. each device is designed to monitor changes in state in the system. (sprinkler waterflow, low air pressure in a system, an improperly open or closed valve, to name a few.) these devices are designed to send an electrical current or signal of high or low voltage to a device(bell or siren) or to an alarm or control panel. The terminals on these devices are similar. They have a "common" terminal. Next, they have an "normally open" terminal; which means the circuit is open normally, but closes during a change in state. The circuit is supervised with a end of line resistor in the circuit, hence an "open loop"

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16y ago
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12y ago

When a sprinkler head gets hot enough it opens a valve which allows water to flow to put out the perceived fire. Once this happens the water will flow until it is exhausted or someone manually turns water off. If it were closed loop, it would recognize the temperature and perhaps control the amount of water supplied and it would turn off when the fire was out. In other words there is no feedback from the system to govern what the sprinkler does after it is activated.

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Q: How does a sprinkler system work as an open loop system?
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What is open loop and close loop system?

Q: What is the difference between 'Open Loop' and 'Closed Loop'? A: When the engine is first started, and rpm is above 400 rpm, the system goes into 'Open Loop' operation. In 'Open Loop', the ECM will ignore the signal from the Oxygen (O2) sensor and calculate the air/fuel ratio based on inputs from the coolant and MAF sensors, but mostly from a pre-programmed table in the memcal. The system will stay in 'Open Loop' until the following conditions are met: 1. The O2 sensor has varying voltage output, showing that it is hot enough to operate properly. (This depends on temperature) 2. The coolant sensor is above a specified temperature about 40oC/104oF. 3. A specific amount of time has elapsed after starting the engine. The specific values for the above conditions vary with different engines and are stored in the mem-cal. When these conditions are met, the system goes into 'Closed Loop' operation. In 'Closed Loop', the ECM will calculate the air/fuel ratio (injector on-time) based on the various sensors but mainly the O2 sensor. This allows the air/fuel ratio to stay very close to 14.7:1.


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Why kirchhoff's voltage law is applicable for open circuit?

Kirchoff's Voltage Law does not work, per se, for open circuits. You need a closed circuit for it to make any kind of sense.The signed sum of the voltage drops going around a series circuit is equal to zero.That means you have a closed circuit.However, it can be argued, correctly, that an open circuit is simply one that has two nodes with infinite resistance between them. Assuming that all of the other nodes have something less than infinite resistance between them, then Kirchoff's law does work, of sorts, in that the voltage drop across all nodes that are not voltage sources will be zero, because there is no current, and the voltage drop across the two nodes with infinite resistance will be equal to the sum of the voltage rises across the voltage sources. Current sources in such a circuit will not work, because, with zero current, they would attempt to generate infinite voltage.AnswerKirchhoff's Voltage Law does indeed apply to an open circuit, because the voltage drop across the open part of the circuit is numerically equal to the supply voltage and, hence, the algebraic sum of the voltage drops around that particular loop is zero.Kirchoff's Voltage Law does not work, per se, for open circuits. You need a closed circuit for it to make any kind of sense.The signed sum of the voltage drops going around a series circuit is equal to zero.That means you have a closed circuit.However, it can be argued, correctly, that an open circuit is simply one that has two nodes with infinite resistance between them. Assuming that all of the other nodes have something less than infinite resistance between them, then Kirchoff's law does work, of sorts, in that the voltage drop across all nodes that are not voltage sources will be zero, because there is no current, and the voltage drop across the two nodes with infinite resistance will be equal to the sum of the voltage rises across the voltage sources. Current sources in such a circuit will not work, because, with zero current, they would attempt to generate infinite voltage.Read more: http://wiki.answers.com/Why_kirchhoff's_voltage_law_is_applicable_for_open_circuit#ixzz1i2fWNqfN


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What effect will occur if the intermediate switch is replaced by a double pole switch?

The circuit will not work. In a three way lighting circuit system the middle switch needs to cross the traveller wires to be effective. A double pole switch in the circuit will just open both traveller wires and disrupt the current flow in both wires. No current flow, no lights.

Related questions

How does a sprinkler system work?

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How does sprinkler systems work?

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What is open loop and close loop system?

Q: What is the difference between 'Open Loop' and 'Closed Loop'? A: When the engine is first started, and rpm is above 400 rpm, the system goes into 'Open Loop' operation. In 'Open Loop', the ECM will ignore the signal from the Oxygen (O2) sensor and calculate the air/fuel ratio based on inputs from the coolant and MAF sensors, but mostly from a pre-programmed table in the memcal. The system will stay in 'Open Loop' until the following conditions are met: 1. The O2 sensor has varying voltage output, showing that it is hot enough to operate properly. (This depends on temperature) 2. The coolant sensor is above a specified temperature about 40oC/104oF. 3. A specific amount of time has elapsed after starting the engine. The specific values for the above conditions vary with different engines and are stored in the mem-cal. When these conditions are met, the system goes into 'Closed Loop' operation. In 'Closed Loop', the ECM will calculate the air/fuel ratio (injector on-time) based on the various sensors but mainly the O2 sensor. This allows the air/fuel ratio to stay very close to 14.7:1.


How fire doors work?

wondoor.com shows a video of the doors in operation. Normally an alarm or sprinkler system activates it and the door closes


What are the best and where do I find more info on a sprinkler system?

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How does Open loop System in automobile work?

I'll assume that you are referring to how the fuel injection system operates when it runs open loop vs. closed loop. In brief, a modern car's engine has a computer that controls how much fuel to deliver to the cylinders via the fuel injectors. It takes into account many things including the temperature of the air and engine, the speed of the engine, the load on the engine, etc. Based on all these inputs, it checks a table that was created by the designing engineers and determines how much fuel to deliver. However, the table cannot possibly take into account all the variables that exist in the real world. So the system is designed to measure the amount of oxygen left over in the exhaust using an O2 sensor. This information is used by the computer to make small corrections to the values from the table. The goal is to get the best possible combination of fuel economy, performance, and emissions. When this is occurring, the system is said to be running closed loop. There are times, such as when the engine is cold or when the driver floors the gas pedal that the system is designed to only use the information from the table and to ignore the O2 sensor. Under these conditions the system is said to be running open loop.